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emmasim [6.3K]
3 years ago
9

How much dirt is there in a hole 3 feet deep, 6 ft long and 4 ft wide?

Mathematics
2 answers:
jasenka [17]3 years ago
4 0
Ok its a hole :) hope this helped
borishaifa [10]3 years ago
3 0
None. There can't be any dirt in it because it's a hole.
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find the value of tan (a-b) if cos a=4/5 on the interval (270, 360) and sin b=-5/13 on the interval (270, 360)
Rudiy27

We can find a and b using inverse trig functions,

\cos(a)=\frac{4}{5}\implies a=\arccos\Big(\frac{4}{5}\Big)\approx36.87 \\\sin(b)=-\frac{5}{13}\implies b=\arcsin\Big(-\frac{5}{13}\Big)\approx-22.62

\tan(36.87-(-22.62))\approx1.7

Hope this helps.

7 0
3 years ago
A quality inspector inspect random box of 50 tablets. He discovers 2 are defective. In an order of 2,000 tablets,how many are li
oksano4ka [1.4K]

Answer:

80

Step-by-step explanation:

So if 50 tablets are made and 2 are defective then it’s 50:2. That means for every 50 tablets are made 2 are defective. And since 50 goes into 2000 40 times, you would multiply 40 x 2 to get 80, the number defective tablets

7 0
3 years ago
HELP!!!!!!!!!!!
Svetradugi [14.3K]

Using the mean concept, it is found that:

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

-----------------------

The mean of a data-set is given by the <u>sum of all observations divided by the number of observations</u>.

In this problem:

  • The data-set is her swim time relative to her goal, which is: {1.25, -1, 2.25, 0, -2.}
  • 5 observations.

Thus, the mean is:

M = \frac{1.25 - 1 + 2.25 + 0 - 2}{5} = 0.1

Relative to Sabrina's goal, her average swim time over the last five weeks is 0.1 hours.

A similar problem is given at brainly.com/question/24787716

7 0
2 years ago
6x + 9 &lt; 63<br> what is x?
Natalija [7]
6x + 9 < 63

Subtract 9 from both sides.

6x < 54

Divide 6 by both sides.

x < 9
7 0
2 years ago
Read 2 more answers
Question Help
lorasvet [3.4K]

Answer:

The speed of the boat is 20 km/hr

Step-by-step explanation:

Let s be the speed of boat in still water

Let d be the distance

Upstream speed = s-4

Jane took 30 min to drive her boat upstream to water-ski at her favorite spot.

So, Distance traveled in upstream =Speed \times time =(s-4) \times \frac{30}{60}

Downstream speed = s+4

So, Distance traveled in downstream = Speed \times time =(s+4) \times \frac{20}{60}

So, (s-4) \times \frac{30}{60}=(s+4) \times \frac{20}{60}

30s-120=20s+80

10s=200

s=20

Hence The speed of the boat is 20 km/hr

6 0
2 years ago
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