I assume you mean the equation
Since i = √(-1), we have i⁴ = 1 and so i⁵ = i. Then 2x + 3 must be some multiple of 5.
Now just check for which of the given choices that this holds:
x = 16 ⇒ 2x + 3 = 35 (yes)
x = 11 ⇒ 2x + 3 = 25 (yes)
x = 10 ⇒ 2x + 3 = 23 (no)
x = 14 ⇒ 2x + 3 = 31 (no)
Answer: Parallelogram is a kind of quadrilateral where as there are some quadrilaterals (like trapezoid , kite, .. ) that do not satisfy the properties of parallelograms.
Step-by-step explanation:
A quadrilateral is a closed polygon having fours sides.
A parallelogram is a kind of quadrilateral having following properties:
Its opposite sides and opposite angles are equal.
The sum of adjacent angles is 180°.
The diagonal of parallelogram bisect each other.
A Trapezoid is also a quadrilateral . It has only one pair of parallel sides. (The other one are not parallel).
So , all quadrilaterals not parallelograms.
Therefore, parallelograms are always quadrilaterals but quadrilaterals are sometimes parallelograms because parallelogram is a kind of quadrilateral where as there are some quadrilaterals (trapezoid , kite, .. ) ) that do not satisfy the properties of parallelograms.
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8x + 3× + 9x = 180
20x = 180
x = 180/20
x = 9
The smallest angle is: 3×9 = 27 degrees
Note: 180 degrees is the sum of angles in a triangle
Answer:
10:12
15:18
20:24
25:30
Step-by-step explanation:
you could just multiply 5 and 6 by the same number so you would get ratios that are equal to each other so for example for 10:12 5 and 6 is getting multiplied by 2
Answer:
(4,0)
Step-by-step explanation:
we have
----> inequality A
----> inequality B
we know that
If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)
Verify each ordered pair
case 1) (4,0)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is true
so
the ordered pair makes both inequalities true
case 2) (1,2)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 3) (0,4)
<em>Inequality A</em>
----> is not true
so
the ordered pair not makes both inequalities true
case 4) (2,1)
<em>Inequality A</em>
----> is true
<em>Inequality B</em>
----> is not true
so
the ordered pair not makes both inequalities true
