SOMEONE HELP IM STUCK PLEASE HURRY

Mathematics

2 answers:

umka21 [38]3 years ago

5 0

Answer:

I got a question like that, so the answer is most likely "c"

Schach [20]3 years ago

5 0

Answer:

Option C

Step-by-step explanation:

3 subtracted from the product of 7 and number b

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AleksandrR [38]

Answer:

R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Step-by-step explanation:

Squaring both sides of equation:

I^2 = (ER)^2/(R^2 + (WL)^2)

<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)

<=>(ER)^2 - (IR)^2 = (IWL)^2

<=> R^2(E^2 - I^2) = (IWL)^2

<=> R^2 = (IWL)^2/(E^2 - I^2)

<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]

Hope this helps!

7 0

3 years ago

Answer...............

aev [14]

In the given graph point B is a relative maximum with the coordinates (0, 2).

The given function is $y=x^{4}-2x^{2} +1$ .

In the given graph, we need to find which point is a relative maximum.

<h3>What are relative maxima?</h3>

The function's graph makes it simple to spot relative maxima. It is the pivotal point in the function's graph. Relative maxima are locations where the function's graph shifts from increasing to decreasing. A point called Relative Maximum is higher than the points to its left and to its right.

In the graph, the maximum point is (0, 2).

Therefore, in the given graph point B is a relative maximum with the coordinates (0, 2).

To learn more about the relative maximum visit:

brainly.com/question/2321623.

#SPJ1

8 0

2 years ago

Find the vertex of y=-x^2-4x

Kay [80]

The vertex would be (-2,4)

3 0

4 years ago