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3 years ago

3 to the -4 power simplified in fraction form

Mathematics

1 answer:

Lynna [10]3 years ago

6 0

Answer:

One/eighty one

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F(x) = 2^x what is the domain ? range ? asymptote ? and transformation

erica [24]

y=2x

Step-by-step explanation:

I dont know what else there is sry

7 0

3 years ago

Pls help i will provide picture

VashaNatasha [74]

Answer:

A. 4

Step-by-step explanation:

First, we can try the first option. 2/4 is equivalent to 6/12 when you multiply the fraction by 3 to get a common denominator. Since 6/12 is larger than 4/12, and the question has 1 answer, 4 is the only value that satisfices the statement and is the answer.

6 0

2 years ago

Can anyone help with this?

Mademuasel [1]

Answer:

error

Step-by-step explanation:

8 0

4 years ago

Which statement describes if there is an extraneous solution to the equation √x-3 = x-5? A. there are no solutions to the equati

Brrunno [24]

Remember that an extraneous solution of an equation, is the solution that emerges from solving the equation but is not a valid solution.

Lets solve our equation to find out what is the extraneous solution:
 $\sqrt{x-3} =x-5$
$(\sqrt{x-3})^2 =(x-5)^2$
$x-3=x^2-10x+25$
$x^2-11x+28=0$
$(x-4)(x-7)=0$
$x-4=0$ and $x-7=0$
$x=4$ and $x=7$

So, the solutions of our equation are $x=4$ and $x=7$ . Lets replace each solution in our original equation to check if they are valid solutions:
- For $x=7$
$\sqrt{x-3} =x-5$
$\sqrt{7-3} =7-5$
$\sqrt{4} =2$
$2=2$
We can conclude that 7 is a valid solution of the equation.

- For $x=4$
$\sqrt{x-3} =x-5$
$\sqrt{4-3} =4-5$
$\sqrt{1} =1$
$1 \neq 1$
We can conclude that 4 is not a valid solution of the equation; therefore, 4 is a extraneous solution.

We can conclude that the correct answer is: D. the extraneous solution is x = 4

7 0

3 years ago

The map of a walking trail is drawn a coordinate grid with three points of interest. The trail starts at R(-3,2) and goes to S(2

Nezavi [6.7K]

Answer:

12 units

Step-by-step explanation:

Given that :

R(-3,2)

S(2,2)

T(2,-5).

The total length ;

Distance between two points : √[(x2 - x1)² + (y2 - y1)²]

Distance between R and S :

R = (-3,2)

S(2,2)

√[((2 - (-3))^2 + (2 - 2)^2]

Sqrt(5^2 + 0^2)

D1 = 5 units

Distance between S and T:

S(2,2)

T(2,-5).

D2 = √[(2 - 2)^2 + (-5 - 2)^2]

D2 = sqrt(0^2 + (-7)^2)

D2 = 7 units

Hence, total length = D1 + D2 = (5 + 7) = 12 units

5 0

3 years ago