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2 years ago

I really really need Help asap plz!

Mathematics

1 answer:

SOVA2 [1]2 years ago

8 0

Answer:

Step-by-step explanation:

Hard to say what your draw down menus will offer.

I would guess "...function will be reduced by a factor of 0.8"

or maybe flattened 20%

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Hey guys plz help meee<br><br>the answers have to be in numbers.

Licemer1 [7]

Answer:

$\overrightarrow{AB}=\frac{-9}{-4}$

$\overrightarrow{CD}=\frac{-5}{4}$

Step-by-step explanation:

A vector quantity is represented by $(\frac{y}{x})$

where y = y-coordinate and x = x-coordinate

Since vector AB represents a vector in 3rd quadrant,

It starts from point A and ends at B,

Therefore, coordinates of B are (-9, -4)

$\overrightarrow{AB}$ = $(\frac{-9}{-4})$

Similarly vector CD starts with C and ends at D in the 2nd quadrant,

Therefore coordinates of D will be (-5, 4)

$\overrightarrow{CD}=\frac{-5}{4}$

7 0

3 years ago

PLEASE HELP 20 POINTS

atroni [7]

Answer:

that not 20 point that 10

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

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muminat

Answer lit

Step-by-step explanation:

6 0

2 years ago

Jason has 14 raspberry scones and 35 blackberry scones. He wants to make as many identical bags of scones as possible. Each bag

Natali5045456 [20]

Answer:

7 is the greatest number of bags Jason can fill.

Step-by-step explanation:

Given: Jason has 14 raspberry scones and 35 blackberry scones.

Now, finding the maximum number of bags Jason can fill with equal number of raspberry scones and blackberry scones.

∴ we will be using Greatest common factor (GCF) for knowing the number of bags.

$14 = 2\times 7\\\\35= 5\times 7$

∴ $GCF= 7$

7 is the greatest number of bags that Jason can fill with equal number of raspberry and blackberry scones.

5 0

2 years ago

You need a mean of at least 90 points to advance to the next round of the touch-screen trivia. What score in the fifth game will

lianna [129]

Answer:

At least 98 is needed in the 5th game

Step-by-step explanation:

The missing parameters are:

$Game\ 1 = 95$

$Game\ 2 = 91$

$Game\ 3 = 77$

$Game\ 4 =89$

$Mean = 90$ at least

Required

The score in game 5 to make you advance

Mean is calculated as:

$Mean = \frac{\sum x}{n}$

So, we have:

$Mean = \frac{95 + 91 + 77 + 89 + Game\ 5}{5}$

$Mean = \frac{352 + Game\ 5}{5}$

The mean must be at least 90.

So, we have:

$\frac{352 + Game\ 5}{5} \ge 90$

Multiply both sides by 5

$5 * \frac{352 + Game\ 5}{5} \ge 90 * 5$

$352 + Game\ 5 \ge 450$

Make Game 5 the subject

$Game\ 5 \ge450 - 352$

$Game\ 5 \ge 98$

<em>At least 98 is needed in the 5th game</em>

4 0

2 years ago