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viktelen [127]
2 years ago
13

Sorry for asking a lot of questions, but this quiz is due in 10 minutes and I forgot a lot of things! Helps appreciated!

Mathematics
1 answer:
oee [108]2 years ago
4 0

Answer:

-16

Step-by-step explanation:

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What is the image of the point (-7,-8)(−7,−8) after a rotation of 270^{\circ}270 ∘ counterclockwise about the origin?
KIM [24]

Answer:

-8,7

i am not sure how to explain it

7 0
2 years ago
(05.05 LC)
Phantasy [73]

Answer:

A. $6

Step-by-step explanation:

We are given the table representing the number of days and the total charges in dollars.

So, the rate of change of the amount is given by, \frac{16-6}{1-0}=\frac{26-16}{2-1}=10

The linear equation representing the situation is,

Total charges = Fee per days + Fixed amount.

i.e. Total charges, y = Rate multiplied by x + Fixed amount (c)

So, substituting the rate and the point (0,6), we get,

6 = 10 × 0 + c

i.e. c = 10

Thus, the equation is,

Total charges, y = Rate multiplied by x + Fixed amount (c)

i.e. y = 10x + 6

Hence, the fixed amount charged is $6.

So, option A is correct.

4 0
4 years ago
If sin theta = 1/3 and tan theta < 0, what is the value of cos theta?
STatiana [176]
If sin Ф=1/3>0 and tan Ф<0; then Ф belongs to the second quadrant and cos Ф will be negative (cos Ф<0).

sin²Ф+cos²Ф=1
(1/3)²+cos²Ф=1
1/9+cos²Ф=1
cos²Ф=1-1/9
cos²Ф=8/9
cos Ф=⁺₋√(8/9)=⁺₋2√2 / 3

We have two possible solutions.
cos Ф=2√2 / 3 This solutions is not possible, because in this case cos Ф has to be negative (cos Ф<0)

cos Ф=(-2√2) / 3 this solutions is right.

answer:B. -2 square root 2 /3    (or    (-2√2) /3  )
5 0
3 years ago
Rearrange the equation so r is the independent variable.<br><br> 10q - 5r = 30
Murljashka [212]

Answer:

q = 3 + 1/2r

Step-by-step explanation:

10q - 5r = 30

We want to solve for q

Add 5r to each side

10q - 5r+5r = 30+5r

10q = 30+5r

Divide by 10

10q/10 = 30/10 +5r/10

q = 3 + 1/2r

3 0
4 years ago
Which of the following parametric equations are equivalent to the polar equation r=3 cos theta
Allushta [10]
To solve the problem you must know that to change from Cartesian to polar coordinates you must write:
 x = rcos (θ)
 Where "r" is the radius
 Likewise y = rsin (θ)
 Therefore, in the expression r = 3cos (θ) one can write r as:
 r = x / cos (θ)
 So:
 x / cos (θ) = 3cos (θ)
 x = 3cos ^ 2 (θ)
 The same for y ...
 y = rsin (θ)
 y = 3cos (θ) sin (θ).

  Finally the correct answer is option 2.
 x = 3cos ^ 2 (θ) y = 3cos (θ) sin (θ).
5 0
3 years ago
Read 2 more answers
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