$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\text{use distributive property}\\\\-\dfrac{2}{\not3_1}\cdot\not3^1x+\dfrac{8}{3}+3x=\dfrac{5}{6}\\\\-2x+3x+\dfrac{8}{3}=\dfrac{5}{6}\ \ \ \ |-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8\cdot2}{3\cdot2}\\\\x=\dfrac{5}{6}-\dfrac{16}{6}\\\\\boxed{x=-\dfrac{11}{6}}$

Other method:

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\cdot6\\\\2(-2)(3x-4)+18x=5\\\\-4(3x-4)+18x=5\ \ \ \ |\text{use distributive property}\\\\-12x+16+18x=5\ \ \ \ |-16\\\\6x=-11\ \ \ \ |:6\\\\\boxed{x=-\dfrac{11}{6}}$

7 0

3 years ago

Read 2 more answers

help me do pls.If u don't know how to do,pls don't do or else u will be reported.I need it under 25 min thank u <3

nevsk [136]

F is proportional to 1/x^2
distance = x
A reduction of 25 percent = 0.75x
Let’s put this in place of x
F = 1/(0.75x)^2
And simplify
F = 1/0.5625x^2

So you need to find the percentage increase from 1/x^2 to 1/0.5625x^2

So what does 1/x^2 multiply by to give 1/0.5625x^2

Written as an equation it is y/x^2 = 1/0.5625x^2
Multiply both sides by x^2
y = 1/0.5625
y = 1.778 (rounded to 3 decimal points)

So the decimal multiplier is 1.778 and so the percent increase is approximately 77.8%

8 0

2 years ago