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Yakvenalex [24]
2 years ago
7

You improve your time running a course by 5 seconds in week one, by 3 seconds in week two, and by 4 seconds in week three. What

is the mean weekly change in your running time?
Mathematics
1 answer:
wariber [46]2 years ago
3 0

Answer:

\displaystyle \bar x=4\ sec

Step-by-step explanation:

<u>Average Value </u>

The mean or average of a number n of measurements is defined as the sum of all values divided by n.

\displaystyle \bar x=\frac{\sum x_i}{n}

The running times in seconds are being improved by the following numbers:

5, 3, 4

This is the dataset where we have to find the mean value. Here n=3. Applying the formula:

\displaystyle \bar x=\frac{5+4+3}{3}

\displaystyle \bar x=\frac{12}{3}

\displaystyle \bar x=4\ sec

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Answer:

Only B and C are always true.

Step-by-step explanation:

To analyse which statements are always true, we go through the process of finding confidence intervals for sample means, from the start.

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From this expression, it is evident that the margin of error determines how wide the confidence interval would be.

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Margin of Error = (Critical value) × (Standard deviation of the distribution of sample means)

Since no information about the population standard deviation is provided, the critical value is obtained using t-distribution.

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The higher the confidence level, the higher the critical value and the higher the margin of error leading to a wider range.

Hence, a confidence interval of 95% will have a higher critical value than a confidence interval of 90%. Hence, statement C is proved once that 'for n = 100, the 95% confidence interval will be wider than the 90% confidence interval'.

After obtaining the critical value, we then obtain the standard deviation of the distribution of sample means or simply the standard error of the mean. This is given as

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where σ = standard deviation; which isn't given. The standard deviation might be high enough to guarantee that the Margin of error is high too for the confidence interval to contain 115 or low enough to ensure that the Margin of error is very small and the confidence interval will not contain 115.

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The point is, it isn't always sure that the resulting interval.would contain 115. So, statement A isn't always true.

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The 95% confidence interval for n = 100 will be more narrow than the 95% confidence interval for n = 50.

Hence, Only B and C are always true.

Hope this Helps!!!

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I think these should help.

Step-by-step explanation:

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