Cross out the 6 make it a 5 then make the 0 a 10 then cross the 10 out make it a 9 and the 8 an eighteen then subtract it all
Answer:
28(1 + 2t +w)
Step-by-step explanation:
28 + 56t + 28w.
Factor out a 28 from the expression.
28(1 + 2t + w)
1) b=1
-3+1=3b-5
Add 3b to both sides.
1=6b-5
Add 5 to both sides
6=6b
Divide both sides by 6
b=1
2) t=11
(1/2)t+7=(3/2)t-4
Subtract 1/2t from both sides.
7=t-4
Add 4 to both sides.
t=11
3) x=-0.878
-2.3 +1.2x=5.9-2.9x
Subtract 1.2x from both sides
-2.3=5.9-4.1x
Add 5.9 to both sides.
3.6=-4.1x
Divide by -4.1
x=-0.878
4)No solution
-7y-21=-3y-21
Add 3y to both sides.
-4y-21=-21
Add 21 to both sides
-4y=0
Imagine we drew a line from the centre (2,0) to the point (0,4).
Essentially the line<u> we drew from the centre to that point on the circle is perpendicular to the tangent line slope-wise</u>.
The <u>slope of that line from the centre to the point is -2</u> based on the slope's equation or formula.
slope = 
Therefore the <u>tangent equation's slope is 1/2</u> since any perpendicular line's slope is the negative reciprocal of the original line's slope.
By<u> using the point-slope form, we must have the point on the tangent plane (0,4) and the slope we found which is 1/2</u>.

Hope that helps!
Let z = sin(x).
.. z^2 -2z = 2
.. z^2 -2z +1 = 3
.. (z -1)² = 3
.. z -1 = ±√3
.. z = 1 -√3 . . . . . the positive solution is extraneous
sin(x) = 1 -√3