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jek_recluse [69]
3 years ago
8

Define identity theft. What are the possible ramifications of having your identity stolen? Briefly describe several ways in whic

h you can take measures to prevent identity theft.
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
5 0

Answer:

identity theft is when someone gets acces to your identity and uses it to like buy things and sign stuff you actually didnt do

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Suppose a linear transformation Upper T : Bold Upper R squared right arrow Bold Upper R squared is formed by taking a rotation c
kotykmax [81]

Answer:

All points on line x+y = 0 or x-y=0 will satisfy the transformation.

Step-by-step explanation:

Let (x, y) be the general such point.

Hence rotating it by 180 deg. counterclockwise will give us (-y,-x).

Reflecting (-y,-x) on x axis gives us (-y,x).

Hence if (x,y) = (-y,x) then all ( x, y) where x = -y or x+y = 0 or x=y or x-y=0 will satisfy this condition.

All points on line x+y = 0 or x-y=0 will satisfy the transformation.

8 0
3 years ago
Writing all Solving Linear Equations in Ule vaDe
zhannawk [14.2K]
P=6.50*10-18.00
hope this helped!❤️
3 0
3 years ago
Read 2 more answers
What value of x makes the equation true?
Ratling [72]

Answer:

x=5

Step-by-step explanation:

x=5

3 0
3 years ago
Read 2 more answers
Help needed plez<br><br>Ans in (ii) is 1.5
Deffense [45]
OK first let's check the x=1.5. 

y = \frac x 6 (x^2 - 10)

y = 1-2x

1-2x = \frac x 6 (x^2 - 10)

6-12x = x^3 - 10 x

x^3 + 2x-6 = 0

Oh my, that's called a depressed cubic, no x^2 term. There's a formula for these very much like the quadratic formula but you're probably not quite old enough for that.  Anyway, x\approx 1.45616 \approx 1.5 is a solution, but that's not what they're asking.  They are asking us to compare 

x^3 + 2x-6 = 0

with

x^3 + bx^2 + cx + d = 0

and conclude b=0, c= 2, d=-6

It turns out we did need all the rest of it.  Save those brain cells, there's lots more math coming.


~~~~~~~~~~~~~~

I love it when the student asks for more.  Here's the formula for a depressed cubic. I won't derive it here (though I did earlier today, coincidentally, but I'm probably not allowed to link to my Quora answer "what led to the discovery of complex numbers" from here).  We use the trick of putting coefficients on the coefficients to avoid fractions.

x^3 + 3 p x = 2 q

has solutions

x = \sqrt[3] { q - \sqrt{p^3 + q^2} } + \sqrt[3] {q + \sqrt{p^3 + q^2} } &#10;&#10;


That's pretty simple, though sometimes we end up having to take the cube roots of complex numbers, which isn't that helpful.  Let's try it out on


x^3 + 2x=6


That's p=2/3, q=3 so

x = \sqrt[3] { 3 - \sqrt{(2/3)^3+9} } + \sqrt[3] {3 + \sqrt{(2/3)^3+9} }

x = \sqrt[3] { 3 - \sqrt{753}/9 } +\sqrt[3]{3 + \sqrt{753}/9 }

x \approx 1.4561642461359084609748069666






6 0
3 years ago
Explain how to find the product of 3/7 X 7/9 . Use complete sentences in your answer.
yawa3891 [41]

Answer:

1/3 simplifed.

Step-by-step explanation:

To find the product of 3/7*7/9. We can multiply top and bottom. Top: 3*7=21 Bottom: 7*9=63. Our final answer is just the Top/Bottom= 21/63. We can also simplify this into 1/3 which is our final answer.

4 0
3 years ago
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