Answer:
the probability that exactly 1 received a special accommodation is 0.3079
Step-by-step explanation:
Step 1: define the variable
x= the number of students who received a special accommodation.
Step 2: define the distribution of this variable
x ~ binomial distribution ( p=0.02, n=25)
this is because x is the number of succes in 25 trials.
Step 3: using the binomial distribution formula
P(x=1)= (25C1)*(0.05^1)*(1-0.05)^(25-1)=0.3079
where (25C1) is a combination
Let's actually find the line of best fit...
m=(nΣyx-ΣyΣx)/(nΣx^2-ΣxΣx)
m=(11*836-130*55)/(11*385-3025)
m=2046/1210
m=93/55
b=(Σy-93Σx/55)/n
b=(55Σy-93Σx)/(55n)
b=(7150-5115)/(55*11)
b=185/55, so the line of best fit is:
y=(93x+185)/55
A) The approximate y-intercept (the value of y when x=0) is 185/55≈3.36.
Which means that those who do not practice at all will win about 3.36 times
B) y(13)=(93x+185)/55
y(13)≈25.34
So after 13 months of practice one would expect to win about 25.34 times.
Answer:
answer b is b=2c+a okay it is right answer
Answer: C is the answer.
Step-by-step explanation:
It is 5/8 because, there is 3 out of 8 chances of the event happening. The rest of the chances, that is 5 out of eight chances, that are not going to happen.
Cylinder: 1²(3) = 3
3(9) =27
Prism: 4x3x6 =72
Total: 72+27 = 99in³
