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xz_007 [3.2K]
3 years ago
7

What is an example of social? (yall dont gotta answer) who wanna talk. im bored.

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
3 0

Answer: An example of social is kids laughing and playing together. and since u really don't want an answer hi hope u get a good grade on whatever this is

Step-by-step explanation:

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What is the scale factor from ABC to DEF?<br> (20 points)
NeX [460]

Answer:

C.1/6

Step-by-step explanation:

yan po ung tamang sagut thank you

7 0
2 years ago
If EF=2x-12, FG= 3x-15, and EG=23, find values of x, EF, and FG
velikii [3]

we have that


*-------------------------*--------------------------------*

E                            F                                     G


EF=2x-12

FG= 3x-15

EG=23


we know that


EF + FG = EG


so

[2x - 12] + [3x - 15] = 23 simplify

5x - 27 = 23 add 27 to both sides

5x = 50 divide both sides by 5

x = 10

EF=2x-12-------> EF=2*10-12-------> EF=8

FG= 3x-15------> FG=3*10-15------> FG=15



therefore


the answer part a) is

the value of x is 10


the answer part b) is

the value of EF is 8


the answer part c) is

the value of FG is 15

6 0
3 years ago
Jelaskan ciri-ciri lingkungan bersih tolong di jawab yaah ​
rusak2 [61]

Answer:

huh hi what is the question?????

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which is greater,,, 3/6 or 2/5
Karolina [17]
3/6 is the answer

3/6is 0.50 and 2/5 is 0.40

Just divide them
6 0
3 years ago
Read 2 more answers
PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%
Yanka [14]

Answer:

x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}

Second equation:

\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}

Third equation:

\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}

Now we use this value for "x" back in equation 1 to solve for "y":

1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}

And finally we solve for the third unknown "z":

\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12

8 0
3 years ago
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