The equation is at the top, the steps are in between, and the answer is at the bottom
hope this helps
8^2=8x8=16 then you add 4 and subtract 12 which will get you 56. correct me if i’m wrong.
You draw a straight line and then put your number on the line. If you have to find a negative number, you can just go below zero. Positive numbers on a number line are always above zero. Hope this helps!
Answer:

Step-by-step explanation:
Whe have the function 
To solve this equation we must factor.
To factor, we need to find the points where the function is equal to zero. So we use the quadratic formula

Where:
a = 3
b = -6
c = 2
Then

finally the correct answer is 
Answer: Domain of the function represented in the graph is given by he inequality . 2 <_ x _< 10
Step-by-step explanation:
we know that
Observing the graph
The domain is the quantity of yellow paint in millimeters
The domain is the interval -----> [2,10]
All real numbers greater than or equal to 2 and less than or equal to 10
therefore 2 <_ x _< 10
my bad I couldn't put the line under the sign