Answer:
3+y and 12+2y
Step-by-step explanation:
I mean they aren't equivalent because if you do PEMDAS (parenthesis, exponents, multiply, divide, add, subtract) Then, you would do 2 times 6 because parenthesis, that equals 12 so the answer would be
3+y and 12+2y
0.3 or 30%. The probability that Ace pick a banana from a basket that content others fruits is 0.3.
The key to solve this problem is using the equation of probability
where n(A) the numbers of favorables outcomes and n the numbers of possible outcomes.
There are in the basket 10 fruits in total (3 bananas + 4 apples + 3 oranges = 10fruits). Then, extract a fruit can occur in 10 ways, this is n. There is only 3 bananas in the basket, so the fruit that ACE will pick be a banana can occur in 3 ways out of 10, so 3 is n(A).
Solving the equation:

Answer:
X Y and Z are the variables.
Step-by-step explanation
Answer:
12 miles per hour
Step-by-step explanation:
Let speed of boat in still water be "x"
and speed of current be "c"
So, downstream rate would be "x + c"
And, upstream rate would be "x - c"
Now, given c = 4
We can use the distance formula, D = RT, where
D is distance, R is rate, and T is time
to solve this.
Downstream:
D = RT
92 = (x+4)(t)
Upstream:
D = RT
46 = (x-4)(t)
Both the times are same, we can equate both the times. Lets simplify first:
t = 92/(x+4)
and
t = 46/(x-4)
Equate:

Now, cross multiply and solve for x to get our answer:

Speed of Boat (in still water) = 12 mph
Answer:

Step-by-step explanation:
Hello,
let's follow the advise and proceed with the substitution
first estimate y'(x) and y''(x) in function of y'(t), y''(t) and t

Now we can substitute in the equation
![x^2y''(x)+9xy'(x)-20y(x)=0\\ e^{2t}[ \ e^{-2t}(\dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}) \ ] + 9e^t [ \ e^{-t}\dfrac{dy}{dt} \ ] -20y=0\\ \dfrac{d^2y}{dt^2}-\dfrac{dy}{dt}+ 9\dfrac{dy}{dt}-20y=0\\ \dfrac{d^2y}{dt^2}+ 8\dfrac{dy}{dt}-20y=0\\](https://tex.z-dn.net/?f=x%5E2y%27%27%28x%29%2B9xy%27%28x%29-20y%28x%29%3D0%5C%5C%3C%3D%3E%20e%5E%7B2t%7D%5B%20%5C%20e%5E%7B-2t%7D%28%5Cdfrac%7Bd%5E2y%7D%7Bdt%5E2%7D-%5Cdfrac%7Bdy%7D%7Bdt%7D%29%20%5C%20%5D%20%2B%209e%5Et%20%5B%20%5C%20e%5E%7B-t%7D%5Cdfrac%7Bdy%7D%7Bdt%7D%20%5C%20%5D%20-20y%3D0%5C%5C%3C%3D%3E%20%5Cdfrac%7Bd%5E2y%7D%7Bdt%5E2%7D-%5Cdfrac%7Bdy%7D%7Bdt%7D%2B%209%5Cdfrac%7Bdy%7D%7Bdt%7D-20y%3D0%5C%5C%3C%3D%3E%20%5Cdfrac%7Bd%5E2y%7D%7Bdt%5E2%7D%2B%208%5Cdfrac%7Bdy%7D%7Bdt%7D-20y%3D0%5C%5C)
so the new equation is

the auxiliary equation is

so the solutions of the new equation are

with a and b real
as


hope this helps
do not hesitate if you have any questions