Question

A certain lottery requires players to select 7 different numbers, in any order, from 1 to 51 inclusive. How many different sets of 7 numbers can be chosen?

Answer 1

Answer:

$Selection = 345025251$

Step-by-step explanation:

Given

$Total = 51$

$Numbers = 7$

Required

Determine number of selection

It's important that

- The first number can be any of the 51 numbers

- The second number can be any of the 51 numbers

- The third number can be any of the 51 numbers

- The fourth number can be any of the 51 numbers

And so on

Hence, number of selections is:

$Selection = 51 * 51 * 51 * 51 * 51$

$Selection = 51^5$

$Selection = 345025251$ ways