All categories

3 years ago

Help please NO LINKS!!!!! special right triangles (radical answers)

Mathematics

2 answers:

olya-2409 [2.1K]3 years ago

5 0

The answer is 6 root 2

AnnyKZ [126]3 years ago

4 0

Answer:

x = $\sqrt{6}$

Step-by-step explanation:

Since the given triangle is equilateral the all 3 sides would be:

$\sqrt{6} +\sqrt{6}$ or $\sqrt{12}$ . Now we know that the base of the right triangle is $\sqrt{6}$ and the hypotenuse is $\sqrt{12}$ . Therefore we can say;

A² + B² = C²

( $\sqrt{6}$ )² + x² = ( $\sqrt{12}$ )²

6 + x² = 12

x² = 12 - 6

x² = 6

x = $\sqrt{6}$

Therefore; x = $\sqrt{6}$ is the length of x, in simplest radical form.

You might be interested in

3.1 Find the equation of the line passing through (4, 5) and parallel to the line 3x – 2y = 4.

valentinak56 [21]

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

Find the equation of the line passing through (4, 5) and parallel to

3x-2y=4.

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

First of all, We need to convert this equation from standard form (ax+by=c) into slope-intercept form (y=mx+b).

$\rightarrow$ First, add 2y on both sides:-

$\Large\textsf{3x+2y=4}$

$\rightarrow$ Now, subtract 3x on both sides:-

$\Large\textsf{2y=-3x+4}$

$\rightarrow$ Divide by 2 on both sides

$\Large\text{$y=-\displaystyle\frac{3}{2}x +2$}$

$\rule{300}{3}$

Now, let's find the equation of the line that's parallel to the given line.

Remember, if lines are parallel to each other, then their slope's the same.

So the slope of the line that's parallel to the line whose equation we just found, is

$\Large\text{$-\displaystyle\frac{3}{2}$}$

Now let's write the equation in point-slope form:-

$\hookrightarrow\sf{y-y_1=m(x-x_1)}$

Replace numbers with letters, as follows:-

$\sf{y-5=-\displaystyle\frac{3}{2} (x-4)}$

The equation above is the equation in point-slope form.

Incase you need it converted to slope intercept form, refer to the steps below ~

Multiply -3/2 times x and -4:-

$\hookrightarrow\sf{y-5=-\displaystyle\frac{3}{2} x-6}$

Now, Add 5 on both sides:-

$\hookrightarrow\sf{y=\displaystyle\frac{3}{2} x+1}$

$\Uparrow\sf{Our\:equation\:in\:slope\;intercept\;form}$

<h3>Good luck with your studies.</h3>

#TogetherWeGoFar

$\rule{300}{1}$

4 0

2 years ago

Find the center and radius of the circle with the equation:

denpristay [2]

Answer:

It’s 14

Step-by-step explanation:

Just add

6 0

3 years ago

Pythagorean Theorem with Known Legs

stepan [7]

you're given the pythagorean theorem, which is a^2 + b^2 = c^2.

what you're trying to find is ?, which is the number under the radical.

let's pretend one leg is a and the other is b.

a = 9

b = 10

so let's plug it into the equation. we get 9^2 + 10^2 = c^2

so that equals 81 + 100 = c^2

181 = c^2

so c will equal the square root of 181. therefore, ? = 181.

hope i helped! good luck.

5 0

2 years ago

Read 2 more answers

Consider the following three points.(-5,2), (0,6), (6,4)Step 3 of 3: Determine whether the three points are collinear or not col

Anni [7]

Step 1

Collinear points are a set of three or more points that exist on the same straight line. Collinear points may exist on different planes but not on different lines.

Step 2

Graph the points; (-5,2),(0,6),(6,4)

Step 3

Conclude based on step 2

Since the points are not a straight line, we can conclude that the 3 points are not collinear.