You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36
36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3
To find the slope, divide a/b and you will get 2/3.
Answer:
Simplify, x(3) + x(2) + x + 1
Step-by-step explanation:
Answer:
y = 3x + 5
General Formulas and Concepts:
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define variables</u>
Slope <em>m</em> = 3
y-intercept <em>b</em> = 5
<u>Step 2: Write linear equation</u>
y = 3x + 5
Answer:
A. 
Step-by-step explanation:
Each mark represent 0.1 unit, so if you count from 0 to 
you get 0.5 that is exactly the same that (for convention the left of the 0 is taken as negative and the right as positive).
