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Andreas93 [3]
3 years ago
11

What is the equation of a line that passes through the point (5, −4) and is parallel to the line whose equation is 2x + 5y = 10?

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
7 0

Answer:

2x + 5y = -10

Step-by-step explanation:

The x- and y-coefficients will be the same for a parallel line. The constant must be chosen to make the line go through the point.

... 2x + 5y = 2(5) +5(-4) = 10 -20 = -10

Your equation is

... 2x + 5y = -10

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What are the domains and ranges of the graphs
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Answer:

The domain for graph 1 is all real numbers, the range is y >= 0.

The domain for graph 2 is x >= 0, the range is y >= 0

Step-by-step explanation:

Graph 1: The x values are infinite for the graph, the y values will always be above zero and continue to be infinite.

Graph 2: The x values start at 0 and go to the right for infinity, the y values start at 0 and continue to infinity.

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The ice-cream truck had 112 ice-cream bars when it went out on its afternoon route. The driver sold 76 ice cream bars at the fir
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Find the product of (3x + 7y)(3x − 7y)
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Step-by-step explanation:

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3 years ago
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I’m confused on this answer anyone know it?
slamgirl [31]

Answer:

y=\frac{26}{7},\:x=-\frac{15}{7}

Step-by-step explanation:

\begin{bmatrix}4x+5y=10\\ -2x+y=8\end{bmatrix}\\\\\begin{bmatrix}-2\cdot \frac{10-5y}{4}+y=8\end{bmatrix}\\\\

-5+\frac{7y}{2}=8\\\\\mathrm{Multiply\:both\:sides\:by\:}2\\-5\cdot \:2+\frac{7y}{2}\cdot \:2=8\cdot \:2\\-10+7y=16\\y=\frac{26}{7}\\

\mathrm{For\:}x=\frac{10-5y}{4}\\\mathrm{Subsititute\:}y=\frac{26}{7}\\x=\frac{10-5\cdot \frac{26}{7}}{4}\\\\

x=-\frac{15}{7}\\

7 0
3 years ago
Solve 2(x + 1) = 2x + 5.
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Answer:

No solutions

Step-by-step explanation:

2(x+1)=2x+5

Expand the parentheses:

2x+2=2x+5

Subtract 2x from both sides:

2=5

Since this is not true, this equation has no solutions. Hope this helps!

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3 years ago
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