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agasfer [191]
3 years ago
6

Y= x +2 x^2 +y^2=10 solve using any method

Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

(-3, -1) and (1, 3)

»»————- ★ ————-««  

Here’s why:  

  • I have graphed the two equations given on a graphing program.
  • When graphed, they pass at points (-3, -1) and (1,3). Therefore, they are the solutions to the system.

⸻⸻⸻⸻

See the graph attached.

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

Virty [35]3 years ago
7 0

Answer:

{ \tt{y = x + 2 -  -  - (a)}} \\ { \tt{ {x}^{2} +  {y}^{2}  = 10 -  -  - (b) }} \\ substitute \: for \: y \: in \: (b) :  \\ { \tt{ {x}^{2}  +  {(x + 2)}^{2} = 10 }} \\ { \tt{ {x}^{2} +  {x}^{2} + 4x + 4 = 10  }} \\ { \tt{2 {x}^{2}  + 4x  - 6 = 0}} \\ { \tt{ {x}^{2} + 2x - 3 = 0 }} \\ { \boxed{ \bf{x = 1 \: and \:  - 3}}} \\ in \: (a)  :  \\ y = x + 2 \\ { \boxed{ \bf{y = 3 \: and \:  - 1}}}

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