Answer:
The initial speed of the ball was 26.2 m/s
Explanation:
When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:
we need to obtain the time taken to go down.
We have a horizontal displacement and the time taken to stop, so:
so:
Answer:
The velocity of the hay bale is - 0.5 ft/s and the acceleration is 
Solution:
As per the question:
Constant velocity of the horse in the horizontal, 
Distance of the horse on the horizontal axis, x = 10 ft
Vertical distance, y = 20 ft
Now,
Apply Pythagoras theorem to find the length:
Now,
(1)
Differentiating equation (1) w.r.t 't':
where
= Rate of change of displacement along the horizontal
= Rate of change of displacement along the vertical
= velocity along the x-axis.
= velocity along the y-axis
Acceleration of the hay bale is given by the kinematic equation:
Constant = straight line
“Travels at constant negative acc.”
Which is negative slope
Solution: B. Straight line w/ neg. slope
Answer:
<h2>441 J</h2>
Explanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 30 × 9.8 × 1.5
We have the final answer as
<h3>441 J</h3>
Hope this helps you
2.1) (i) W = mg downwards
(ii) N = R = Normal Reaction from the ground upwards
(iii) Fe = Force of engine towards the right
(iv) f = friction towards the left
(v) ma = Constant acceleration towards right.
2.2.1)
v = 25 m/s
u = 0 m/s
∆v = v - u = (25 - 0) m/s = 25 m/s
x = X
∆t = 50 s
a = 0.5 m/s².
2.2.2)
F = ma = 900 kg × 0.5 m/s² = 450 N.
2.2.3)
2.3)
Fe = f + ma
Fe - f = ma
For velocity to be constant,
a should be 0, or, a = 0,
Fe = f = 270 N
2.4.1)
v = 0
u = 25 m/s
a = -0.5 m/s²
v = u + at
t = -u/a = -(25)/(-0.5) = 50 s.
2.4.2)
x = -625/(2×(-0.5)) = 625 m.
