When is at the end of the runway the velocity of the plane is given by the equation

where s=1800 m is the runway length. Thus
At half runway the velocity of the plane is

Therefore at midpoint of runway the percentage of takeoff velocity is
‰
Answer:
d. 5 ohms
Explanation:
For resistors in parallel, the equivalent resistance is found with:
1/Req = ∑(1/R)
1/R = 1/15 + 1/15 + 1/15
1/R = 3/15
R = 15/3
R = 5
28 degrees celsius converts to 82.4 degrees in Fahrenheit :)