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leva [86]
4 years ago
8

Preventing projects​

Physics
1 answer:
arlik [135]4 years ago
3 0

Explanation:

please Mark me aa brainliest

then i will ans you

so please

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sukhopar [10]
Yes they are involved
5 0
3 years ago
If a car is traveling 35 m/s for 200 seconds, how far will the car travel?
Nana76 [90]

Answer:

7.14285714286

Explanation:

4 0
3 years ago
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A toy floats in a swimming pool. The buoyant force exerted on the toy depends on the volume ofa. none of these choices.b. all th
Citrus2011 [14]

Answer:c

Explanation:

The buoyancy force on toy depends upon the volume of toy under pool water.

According to Archimedes principle buoyant force on a floating body depends upon the weight of displaced liquid by object.

Buoyancy force is given by

F_b=\rho _f\times V\times g

where \rho _f=density of fluid

V=volume of object under water

g=acceleration due to gravity

6 0
4 years ago
If you apply an unbalanced force to this object it will ______. Mention all that will apply: change velocity, accelerate, change
Papessa [141]

Answer:

All of them: change velocity, accelerate, change position

Explanation:

We can answer this question by using Newton's second law:

F = ma

where

F is the net force on the object

m is the mass of the object

a is the acceleration

We notice that when there is an unbalanced force on the object, F\neq 0, and therefore

a\neq 0

whcih means that the object will accelerate.

But acceleration is the rate of change of velocity, v:

a=\frac{\Delta v}{\Delta t}

And so,

\Delta v \neq 0

which means that the object will change velocity.

If the object is changing velocity, this means that it is also moving: therefore, the position of the object must be changing, so also the option "change position" is correct.

6 0
3 years ago
A 310-g air track cart is traveling at 1.25 m/s and a 260-g cart traveling in the opposite direction at 1.33 m/s. What is the sp
UNO [17]

Answer:

v_{CM}=0.0732\ m/s

Explanation:

given,

mass of the cart 1, m₁ = 310 g

speed of car 1 , v₁ = 1.25 m/s

mass of cart 2, m₂ = 260 g

speed of cart 2, v₂ = -1.33 m/s

speed of center of mass

v_{CM}=\dfrac{m_1v_1 + m_2 v_2}{m_1 + m_2}

v_{CM}=\dfrac{0.31\times 1.25 +0.26\times (-1.33)}{0.31+0.26}

v_{CM}=\dfrac{0.0417}{0.57}

v_{CM}=0.0732\ m/s

Hence, speed of center of mass of the system is equal to 0.0732 m/s

7 0
3 years ago
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