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3 years ago

Help me please!!! Please

Mathematics

1 answer:

nasty-shy [4]3 years ago

4 0

Answer:

<h3>ddndndndkfk</h3>

Step-by-step explanation:

menfnfnfncncnleoemellzlsld j

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Evaluate the expression (3.2)².

Ludmilka [50]

Answer:

Step-by-step explanation:

3*2=6

6^2=6*6

=36

7 0

3 years ago

Pls help me with this pre-calc question on vectors!!

alexdok [17]

E = (-12,15,-9)
F = (-12, 17 , -22 )
EF = F - E = (-12, 17 , -22 ) - (-12,15,-9)
= ( 0 , 2 , -13 ) = 2j - 13 k
The correct answer is option C

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3 years ago

Solve for x. Can somebody help me? I don’t understand how to do this.

Basile [38]

$-1=\dfrac{5+x}{6}\\\\-6=5+x\\\\x=-11$

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3 years ago

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Andre45 [30]

Answer:

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Step-by-step explanation:

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3 years ago

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Step2247 [10]

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

Step-by-step explanation:

Given the points

(-4,1)

(4,3)

Finding the slope between the points (-4,1) and (4,3)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)$

$m=\frac{3-1}{4-\left(-4\right)}$

Refine

$m=\frac{1}{4}$

Point slope form:

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

in our case,

m = 1/4

(x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

$y-y_1=m\left(x-x_1\right)$

$y-1=\frac{1}{4}\left(x-\left(-4\right)\right)$

$y-1=\frac{1}{4}\left(x+4\right)$

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

$y-1=\frac{1}{4}\left(x+4\right)$

5 0

3 years ago