All categories

3 years ago

Pls help me with this pre-calc question on vectors!!

Mathematics

1 answer:

alexdok [17]3 years ago

6 0

E = (-12,15,-9)
F = (-12, 17 , -22 )
EF = F - E = (-12, 17 , -22 ) - (-12,15,-9)
= ( 0 , 2 , -13 ) = 2j - 13 k
The correct answer is option C

You might be interested in

Hi! can you please help me and show me how you got your answer? thank you!

Kamila [148]

Answer:

Step-by-step explanation:multipy -4x and 4 by 2 were the 8x and the -8x would cancel then add and bring down answer of x=15

5 0

3 years ago

How do you do this? please help me

Anastaziya [24]

Answer:

f = 10, g = 4.8 cm

Step-by-step explanation:

Area of ABCE = 60 cm²

Area of ABCD = 48 cm²

So,

Area of ADE = 60-48

=> 12 cm²

Area of ADE = $\frac{1}{2} (Base)(Height)$

Where Area = 12 cm², Base = 4 cm

12 = $\frac{1}{2}(4)(Height)$

Height = 12-2

Height = 10 cm

Where Height is AD

So, AD = 10 cm

Also, AD is parallel and equal to BC $(f)$

So,

f = 10 cm

Now, Finding g

Area of ABCD = $Base * Height$

Where Area = 48 cm², Base = 10 cm

48 = 10 * Height

Height = 48/10

Height = 4.8 cm

Whereas, Height is g

So, g = 4.8 cm

8 0

3 years ago

The square root of 1.85

WARRIOR [948]

Answer:

around 1.36

Step-by-step explanation:

4 0

2 years ago

Simplify the expression by using a double-angle formula. 2 sin 31°cos 31°

qwelly [4]

The double angle formula for the sine is

$\sin(2x) = 2\sin(x)\cos(x)$

The right hand side is exactly your expression, where $x = 31^\circ$

So, rewriting the expression from right to left, we have

$2\sin(31^\circ)\cos(31^\circ) = \sin(2\cdot 31^\circ) = \sin(61^\circ)$

6 0

3 years ago

How to find length of sides for right triangle knowing angles?

kifflom [539]

U can use the cosine or sine rules depending on the question/triangle

3 0

3 years ago