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RUDIKE [14]
3 years ago
13

Pls help me with this pre-calc question on vectors!!

Mathematics
1 answer:
alexdok [17]3 years ago
6 0
E = (-12,15,-9)
F = (-12, 17 , -22 )
EF = F - E = (-12, 17 , -22 ) - (-12,15,-9) 
     = ( 0 , 2 , -13 )      = 2j - 13 k
The correct answer is option C



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Answer is B because brick starts with a B
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Assume that random guesses are made for eight multiple choice questions on an SAT test, so that there are n= 8 trials, each with
alina1380 [7]

Answer:

0.80589

Step-by-step explanation:

So all of the numbers of correct answers less than 4 are 0,1,2,3

We need to calculate the probability for each separately and then add them together.

To find the probability we have to first find the combination. We know that there’s n=8 trials and that p=0.3. So 1-0.3 gives us 0.7.

The combination formula is: ! / (!(−)!)

So the n would always =8, and the r would be 0,1,2,3. So you would have to calculate it for 0,1,2,3 Separately. This can be done by hand or you can use a simple combinations calculator online.

For 0;

The combination is 1,

1 x 0.3^0 x 0.7^8-0 =

0.057648

For 1;

The combination is 8,

8 x 0.3^1 x 0.7^8-1 =

0.19765

For 2;

The combination is 28

28 x 0.3^2 x 0.7^8-2 =

0.296475

For 3;

The combination is 56

56 x 0.3^3 x 0.7^8-3 =

0.254122

All that’s left is to add these four numbers;

0.057647 + 0.19765 + 0.296475 + 0.254122 = 0.80589

4 0
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Help please I'm really confused I will mark a brainliest for correct answer
max2010maxim [7]
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5 0
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antiseptic1488 [7]
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Thirty percent of all customers who enter a department store will make a purchase. Suppose that 6 customers enter the store and
torisob [31]

Answer:

Step-by-step explanation:

Let's use binomial distribution, because we are interested in find the total number of successes in a sequence of n independent experiments.

In probability, a binomial distribution is used in a Bernoulli process. That is, a sequence of experiments of n independent  trials, each asking a dichotomous question, that means it only has two answers. One answer is a success (probability: p) and the other is a failure (probability: 1-p). In this case, every customer who enters in the store is the experiment. If they make a purchase is a success event, taking into account that every purchase decision has to be independent.

P(X=x) = C(n,x)p^{x} (1-p)^{n-x}

x= total number of success

n= total number of experiments

p=probability of success on an indivual trial

C(n,x) = \frac{n!}{x!(n-x)!}

a) x= 5 ------> customers that make a purchase

n= 6 ------> total customers

p=0.3

p(X=5)= C(6,5)(0.3)^{5} (1-0.3)^{6-5} \\p(X=5)=0.102

b) At least 3 customers make a purchase. x ≥ 3

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c) At most 2 customers make a purchase. x ≤ 2

P(X\leq2) = P(X=0) + P(X=1) + P(X=2)\\P(X\leq2) = (C(6,0)(0.3^{0})(0.7)^{6}) + (C(6,1)(0.3^{1})(0.7)^{5}) + (C(6,2)(0.3^{2})(0.7)^{4})\\P(X\leq2) = 0.11765-0.30253-0.32414\\P(X\leq2)=0.7443

d)At least 1 customer makes a purchase. x ≥ 1

P(X\geq 1)=1-P(X=0)\\P(X\geq 1)= 1-C(0,6)(0.3)^{0}(0.7)^{6} \\P(X\geq 1)= 1-0.11765 = 0.8824

e)They must be kind to customers, always willing to help and give information about products clearly and honestly.

Have enough inventory and offer promotions for the purchase of more than one product

Have an agile payment system that avoids rows and delays in purchases.

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