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Pavel [41]
3 years ago
15

Write an equation in point-slope form of the line that passes through (-4,1) and (4,3).

Mathematics
1 answer:
Step2247 [10]3 years ago
5 0

Answer:

An equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

Step-by-step explanation:

Given the points

  • (-4,1)
  • (4,3)

Finding the slope between the points (-4,1) and (4,3)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-4,\:1\right),\:\left(x_2,\:y_2\right)=\left(4,\:3\right)

m=\frac{3-1}{4-\left(-4\right)}

Refine

m=\frac{1}{4}

Point slope form:

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

in our case,

  • m = 1/4
  • (x₁, y₁) = (-4,1)

substituting the values m = 1/4 and the point (-4,1) in the point slope form of line equation.

y-y_1=m\left(x-x_1\right)

y-1=\frac{1}{4}\left(x-\left(-4\right)\right)

y-1=\frac{1}{4}\left(x+4\right)

Thus, an equation in point-slope form of the line that passes through (-4,1) and (4,3) will be:

y-1=\frac{1}{4}\left(x+4\right)

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