Answer:
2022
Step-by-step explanation:
2 + 4x = y
y = 2 + 4(505)
y = 2 + 2020
y = 2022
Answer:
The third one. The square in the top left can only fold to the right or down.... which means there is guaranteed to be an open side remaining on the square.
Answer:
No solution
Step-by-step explanation:

Lets consider the equation 2.
Here we multiply the LHS and RHS with (-1).

Hence,

When we add the equations we get,

As 0 doesn't equal to -1, answer is d) No solution
Step-by-step explanation:
You have found a function r(V(t)). We can see that this function is a one variable function. The variable is time.
So in this specific function we can call r(v(t)), r(t).
So:
![r(t) = \sqrt[3]{ \frac{3 \times (10 + 20t)}{4\pi} }](https://tex.z-dn.net/?f=r%28t%29%20%3D%20%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20%2810%20%2B%2020t%29%7D%7B4%5Cpi%7D%20%7D%20)
If α is the moment that the radius is 10 inches and since the function above gives radius in inches we have to solve the equation:

Which is the same as:
![\sqrt[3]{ \frac{3 \times (10 + 20 \alpha )}{4\pi} } = 10 \\ \frac{3 \times (10 + 20 \alpha )}{4\pi} = 1000 \\ (10 + 20 \alpha ) = \frac{4000\pi}{3} \\ 20 \alpha = \frac{(4000\pi - 30)}{3} \\ \alpha = \frac{(4000\pi - 30)}{60}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B3%20%5Ctimes%20%2810%20%2B%2020%20%5Calpha%20%29%7D%7B4%5Cpi%7D%20%7D%20%20%3D%2010%20%5C%5C%20%20%5Cfrac%7B3%20%5Ctimes%20%2810%20%2B%2020%20%5Calpha%20%29%7D%7B4%5Cpi%7D%20%20%3D%201000%20%5C%5C%20%2810%20%2B%2020%20%5Calpha%20%29%20%3D%20%20%5Cfrac%7B4000%5Cpi%7D%7B3%7D%20%20%5C%5C%2020%20%5Calpha%20%20%3D%20%20%5Cfrac%7B%284000%5Cpi%20-%2030%29%7D%7B3%7D%20%5C%5C%20%20%5Calpha%20%20%3D%20%20%5Cfrac%7B%284000%5Cpi%20-%2030%29%7D%7B60%7D%20)
Answer:
1. Perfect Square
2. Perfect Square
3. Conjugate
4. Conjugate
5. Perfect Square
-I am about 98% sure about these answers.
-An example for a perfect square is (5x+3)(5x+3) and an example for a conjugate is (5x+3)(5x-3). The only difference between the two is the symbol for the second pair of parenthesis.