The perimeter "P" is equal to the length of the base of one triangle multiplied by the "n" number of triangles in the figure plus two times the length of another side. The equation for the perimeter is P = 5n + 14.
We are given triangles. The triangles are arranged in a certain pattern. The length of the base of each triangle is equal to 5 units. The length of the other two sides is 7 units each. We conclude that all the triangles are isosceles. We need to find the relationship between the number of triangles and the perimeter of the figure. Let the perimeter of the figure having "n" number of triangles be represented by the variable "P".
P(1) = 14 + 5(1)
P(2) = 14 + 5(2)
P(3) = 14 + 5(3)
We can see and continue the pattern. The relationship between the perimeter and the number of triangles is given below.
P(n) = 14 + 5n
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Answer:
1 3/8.
Step-by-step explanation:
3 1/4 - 1 7/8
First convert to improper fractions:
3 1/4 = (3*4) + 1 / 4 = 13/4.
1 7/8 = (1 *8)+7 / 8 = 15/8. So we have:
13/4 - 15/8
The Lowest Common Multiple of 4 and 8 is 8 so we convert 13/4 to eighth's
13 / 4 = 13*2 / 4 *2 = 26/8
Finally: we have
26/8 - 15/8 = (26 - 15) /8
= 11 /8
= 1 3/8 (answer)
Answer:
x=8
x=-2
Step-by-step explanation:
∣x−3∣+4=9
= ∣x−3∣=5
<u>Positive term: (x-3)</u>
(x-3) = 5
Rearrange and Add up
x = 8
<u>Negative term: -(x-3)</u>
Multiply
-x+3 = 5
Rearrange and Add up
-x = 2
Multiply both sides by (-1)
x = -2
Answer:
a=1 or a=5/6
Step-by-step explanation:
I'm going to attempt to factor 6a^2-a-5
a=6
b=-1
c=-5
Find two numbers that multiply to be a*c and add to be b.
a*c=-30 =-6(5)
b=-1 =-6+5
So replace -a with -6a+5a in the expression we started with
6a^2-6a+5a-5
now we factor by grouping
6a(a-1)+5(a-1)
(a-1)(6a-5)
Now let's solve the equation:
(a-1)(6a-5)=0
So a=1 or a=5/6
m is equal to 3. Need I say more?
