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slava [35]
2 years ago
10

Please help [photo attachment]

Mathematics
1 answer:
Alexxx [7]2 years ago
5 0
Absolute Zero, also I suggest cropping out your name and teacher for your safety :3 have an amazing day!
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How do you convert binary numbers to decimal numbers
telo118 [61]
An easy method of converting decimal to binary number equivalents is to write down the decimal number and to continually divide-by-2 (two) to give a result and a remainder of either a “1” or a “0” until the final result equals zero.
5 0
3 years ago
Hi can you match these for me :(
podryga [215]

Answer:1c .          3a .             4b .           5d .       2e    

Step-by-step explanation:sorry if wrong not super good

4 0
3 years ago
Find the derivative of y= 1 / x​
givi [52]

Answer:

dy/dx = -1/x^{2}

Step-by-step explanation:

y = 1/x

dy/dx = d/dx(1/x)

=> dy/dx = d/dx(x^{-1})

=> dy/dx = -x^{-2}

=> dy/dx = -1/x^{2}

6 0
3 years ago
Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,
MrRissso [65]

Answer:

4.82\cdot 10^{-4}

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

n-1=51

Therefore, the probability of drawing a three at the 2nd draw is

p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784

Then, at the third draw, the previous 2 cards are not replaced, so there are now

n-2=50

cards in the deck. So, the probability of drawing a jack is

p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08

Therefore, the total probability of drawing an ace, a three and then a jack is:

p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}

4 0
3 years ago
SOMEBODY PLEASE HELP ME!!!!!!!​
kenny6666 [7]

Answer:

50/100

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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