Solve the compound inequality. x+3<0 or 5x>−10

Mathematics

2 answers:

MrRa [10]2 years ago

7 0

Answer:

x < – 3 or x > – 2

Step-by-step explanation:

For x + 3 < 0 :

subtract 3 from both sides of the inequality:

x + 3 – 3 < 0 – 3

x + 0 < – 3

x < –3

For 5x > – 10:

Divide both sides of the inequality by 5 to isolate x:

$\frac{5x}{5} > \frac{-10}{5}$

x > –2

Therefore:

x < – 3 or x > –2

Interval notation: [(– ∞, –3) ∪ (–2, ∞)]

IgorC [24]2 years ago

5 0

Answer:

$x + 3 < 0 \: \: or \: \: 5x > - 10 \\ \\ x < - 3 \: \: or \: \: x > - 2 \\ \\ { \boxed{ \: \: - 3 < x < - 2 \: \: }}$

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Read 2 more answers

Graph 3x + 4y = -10

cricket20 [7]

First, isolate y on one side to find some information about the graph.

3x+4y=-10
4y=-10-3x
y=(-10-3x)/4

Now find out the x and y intercepts of this equation;

(0)=(-10-3x)/4
4x0=-10-3x
0=-10-3x
3x=-10
x=-10/3 or -3.3333 (x-intercept)

y=(-10-3(0))/4
4y=-10
y=-10/4 or -5/2 = -2.5 (y-intercept)

Plot these points onto your graph and connect the lines.

I have attached a graph below, I'm sorry I couldn't do it on paper.

Hope I helped :)