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viktelen [127]
3 years ago
8

Every month, a group of 46 students write essays in a class. Each student writes 2 essays, and each essay

Mathematics
2 answers:
solmaris [256]3 years ago
3 0

Answer: 92000 words

Step-by-step explanation:

46×2=92 essays

92×1000=92000

DaniilM [7]3 years ago
3 0

Answer:

92,000 words

Step-by-step explanation:

1000 words = 1 essay

2 essays = 2000 words

46 students = 2000 × 46

46 = 92000 words

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a plumber charges $45 for the first hour and $30 for each additional hour.how much does he charge if it takes him 4 hours to mak
sveticcg [70]
45+30=75 so 75*4+300 dollars
8 0
3 years ago
Dion is out shopping and finds a basketball jersey originally valued at $128.00. it is now on sale for 75% of the original price
Fittoniya [83]

Answer:

$96

Step-by-step explanation:

$128 X 78/100

= $128 X .75

= $96

Dion would buy it, he's rich

7 0
2 years ago
Anybody know how to solve this?
kirza4 [7]

Answer:

1

Step-by-step explanation:

Anything to the 0 power is 1.

Hope this helps!

:)

6 0
2 years ago
Read 2 more answers
Someone help me with these questions pls-
Andrews [41]

When finding the reciprocal, it is basicaly flipping the numerator and denominator of the number. For instance, the reciporcal of 2 is 1/2, because the denominator of 2 would be 1. For an example more straight forward, the reciporacle of 3/5 is 5/3. This applied to the question goes as followed.

1. 3/5 is 5/3

2. 1/4 is 4

3. 1 is 1

Similarly when dividing fractions or an integer to a fraction, the fraction that is dividing the number turns into the reciprocal then you would multiply.

4.   3/(3/4) is 3*4/3= 4

5.   5/(3/4) is 5*(4/3)= 20/3

6.   8/(4/7) is 8*(7/3)= 56/3

7. 6/(3/5) is 6*(5/3)= 10

8. 2/(5/8) is 2*(8/5)= 16/5

9. 4/(8/9) is 4*(9/8)= 9/2

8 0
2 years ago
Read 2 more answers
| x-3 | &lt; x-3<br><br> can someone give a step by step process on how to do this?
statuscvo [17]

Answer:

There are no solutions to the inequality.

Step-by-step explanation:

|x - 3| < x – 3

1. Separate the inequality into two separate ones.

(1) x – 3 < x – 3

(2) x – 3 < -(x – 3)  

2. Solve each equation separately

(a) Equation (1)

\begin{array}{rcl}x - 3 & < & x - 3\\x & < & x\\\end{array}\\\text{This is impossible. No solutions exist.}

(b) Equation (2)

\begin{array}{rcl}x - 3 & < & -(x - 3)\\x - 3 & < & -x + 3\\x &

For example, if x = 0, we get  

|0 - 3| < 0 - 3 or

3 < -3

4 0
3 years ago
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