A.y=-x+0.5<br> B.y=-x-0.5<br> C.y=x+0.5<br> D.y=x-0.5

Rewrite following sets in roster form or listing form.

pshichka [43]

Answer:

you have to write the name of districts of province no. 7

8 0

3 years ago

What is the solution to the quadratic inequality?

MaRussiya [10]

<h2><em><u>Answer:</u></em></h2><h2><em><u>First, solve each inequality. I'll solve the first one first. </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>7 </u></em></h2><h2><em><u>≥ </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>5 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>12 </u></em></h2><h2><em><u>≥ </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>≥ </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Therefore, x could be any number less than or equal to 6. In interval notation, this looks like: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>] </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>The parenthesis means that the lower end is not a solution, but every number above it is. (In this case, the lower end is infinity, so a parenthesis must be used, since infinity is not a real number and so it cannot be a solution.) The bracket means that the upper end is a solution. In this case, it indicates that not only could </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> be any number less than 6, but it could also be 6. </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Let's try the second example: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>3 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>4 </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>4 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>3 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>2 </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>16 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>3 </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>18 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u>> </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Therefore, x could be any number greater than 6, but x couldn't be 6, since that would make the two sides of the inequality equal. In interval notation, this looks like: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>) </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>The parentheses mean that neither end of this range is included in the solution set. In this case, it indicates that neither 6 nor infinity are solutions, but every number in between 6 and infinity is a solution (that is, every real number greater than 6 is a solution). </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Now, the problem used the word "OR", meaning that either of these equations could be true. That means that either </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> is on the interval </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>] </u></em></h2><h2><em><u> or the interval </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>6 </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>) </u></em></h2><h2><em><u>. In other words, </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> is either less than or equal to 6, or it is greater than 6. When you combine these two statements, it becomes clear that </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> could be any real number, since no matter what number </u></em></h2><h2><em><u>x </u></em></h2><h2><em><u> is, it will fall in one of these intervals. The interval "all real numbers" is written like this: </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>( </u></em></h2><h2><em><u>− </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>, </u></em></h2><h2><em><u>∞ </u></em></h2><h2><em><u>) </u></em></h2><h2><em><u> </u></em></h2><h2><em><u>Final Answer</u></em></h2><h2><em><u>Step-by-step explanation:</u></em></h2>

5 0

3 years ago

Solve x2 + 4x + 1 = 0.

docker41 [41]

Answer: Option C ( $x=-2$ ± $\sqrt{3}$ )