A.y=-x+0.5 B.y=-x-0.5 C.y=x+0.5 D.y=x-0.5

Mathematics

2 answers:

omeli [17]3 years ago

8 0

Answer:

Step-by-step explanation:

postnew [5]3 years ago

3 0

The correct answer is D. Y=x-0.5

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The length of rectangle is represented by x and the width by y. The square of the diagonal of the rectangle is equal to the sum

maksim [4K]

To solve this problem you must apply the proccedure shown below:

1- You have the following information given in the problem above:

- <span>The square of the diagonal of the rectangle is equal to the sum of the squares of the length and the width.
- The length is 25 meters and the diagonal is 45 meters.

2- Therefore, you have:

x: diagonal of the rectangle.

x^2=l^2+w^2

3- You have:

w^2+l^2-x^2=0
w^2+(25)^2-(45)^2=0
w^2-1400=0
w=37.41

The answer is: </span>w^2-1400=0

8 0

3 years ago

Read 2 more answers

Help with math pls cant figure it out

tatyana61 [14]

Answer:

$\frac{5}{4}+or-\frac{3i\sqrt{7} }{4}$

Step-by-step explanation:

You can solve this equation with the quadratic formula which is:

$m_{1,2}=\frac{-b+or-\sqrt{b^{2}-4ac } }{2a}$

All you need to do is rearrange the equation (add $-\frac{11}{2}$ to both sides and then multiply both sides by 2) to get:

$2m^2-5m+11=0$

From this new equation, we can easily see that a = 2, b = -5, and c = 11 AND you don't have to work with as many fractions. Substitute the values for a, b, and c into the quadratic formula to get:

$m_{1,2}=\frac{5+or-\sqrt{(-5)^{2}-4(2)(11) } }{2(2)}$