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vaieri [72.5K]
4 years ago
11

The Sun illuminates ________________________ of the Moon at all times.

Mathematics
2 answers:
RSB [31]4 years ago
8 0
The Sun illuminates "half" of the Moon at all times.
Natali [406]4 years ago
8 0

Answer:

Half

Explanation:

The Sun is at the center of the solar system. It is the source of heat and light. The moon revolves about the Earth while the Earth revolves about the Sun. The Sun, Earth and moon also rotate about their own axis.

The Sun illuminates <u>half</u> of the Moon at all times. This illuminated half does not always faces the Earth. Phases of moon are the shapes of the moon that we see from the Earth because of the portion of the illuminated part that is visible.

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Please help with Geometry homework!!! Will give brainliest and 50 points to whoever answers first!!!
melomori [17]

Answer:

x = 42.5

Step-by-step explanation:

It is said:

If two angles are not corresponding, then they make up 180°. They are more known as supplementary angles.

So the equation is:

a + b = 180°

Substitute

x + 8 + 3 x + 2 = 180°

x + 3x + 8 + 2 = 180°

4x + 10° = 180°

4x = 180° - 10°

4x = 170°

x = 170° ÷ 4

x = 42.5

6 0
3 years ago
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dolphi86 [110]

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3 0
3 years ago
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General solutions of sin(x-90)+cos(x+270)=-1<br> {both 90 and 270 are in degrees}
mixer [17]

Answer:

\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

Step-by-step explanation:

Given:

\sin (x-90^{\circ})+\cos(x+270^{\circ})=-1

First, note that

\sin (x-90^{\circ})=-\cos x\\ \\\cos(x+270^{\circ})=\sin x

So, the equation is

-\cos x+\sin x= -1

Multiply this equation by \frac{\sqrt{2}}{2}:

-\dfrac{\sqrt{2}}{2}\cos x+\dfrac{\sqrt{2}}{2}\sin x= -\dfrac{\sqrt{2}}{2}\\ \\\dfrac{\sqrt{2}}{2}\cos x-\dfrac{\sqrt{2}}{2}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos 45^{\circ}\cos x-\sin 45^{\circ}\sin x=\dfrac{\sqrt{2}}{2}\\ \\\cos (x+45^{\circ})=\dfrac{\sqrt{2}}{2}

The general solution is

x+45^{\circ}=\pm \arccos \left(\dfrac{\sqrt{2}}{2}\right)+2\pi k,\ \ k\in Z\\ \\x+\dfrac{\pi }{4}=\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{4}\pm \dfrac{\pi }{4}+2\pi k,\ \ k\in Z\\ \\\left[\begin{array}{l}x=2\pi k,\ \ k\in Z\\ \\x=-\dfrac{\pi }{2}+2\pi k,\ k\in Z\end{array}\right.

4 0
3 years ago
Solve T = L(5 + RS) for S<br> 0
tino4ka555 [31]

Answer:

Step-by-step explanation:

=5

6 0
3 years ago
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On a circle of radius 7 feet, what wlangke would substend an arc of length 7 feet?
Elenna [48]
Arc length = radius * central angle (in radians)
central angle = arc length / radius
central angle = 7 / 7
central angle = 1 radian
central angle = 57.296 degrees

6 0
3 years ago
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