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Bond [772]
3 years ago
15

−20cos ​2 ​​ x−3cosx=−2 answer in decimals

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
7 0

Here is your answer. 0.117658

Airida [17]3 years ago
3 0

Well, first of all, the equation in your question isn't clear.  I decided that you intended to write the equation

-20 cos²(x) - 3 cos(x) = -2

If this is not the correct equation, then you should stop reading right here.  Everything else from here on is nonsense, and you should report my answer.

= = = = =

If that <u>IS</u> the correct equation, then ...

Multiply each side by -1 . . . 20 cos²(x) + 3 cos(x) = 2

Subtract 2 from each side . . . 20 cos²(x) + 3 cos(x) - 2 = 0

This is a quadratic equation in 'cos(x)' .  I messed around for a while trying to factor it, and then I gave up and used the Quadratic Formula.

Like any other quadratic equation, this one has two roots:

(1).  cos(x) = -119/40  or  -0.475

(2).  cos(x) = 7/40  or  0.175

For the first one, the angle 'x' is <em>118.36°</em>  or  <em>241.64°</em>

For the second one, the angle 'x' is <em>79.92°</em>  or  <em>280.08°</em>

So the original equation ... the one with all the cosines in it ... actually has four (4) solutions.

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That's all of your answers.
7 0
3 years ago
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Sidana [21]
I’m pretty sure it’s x=10 because
8x + 50 = 130
So we would subtract 50 from both sides so it would be 8x = 130 - 50 then it would give us 80 so now we have 8x =80, now we will need to divide the 8 on both sides to get x, so 80/8 equals 10
6 0
3 years ago
SOMEONE HELP ME IM FREAKING OUT I LITERALLY CANT WITH THIS QUESTION IM PRAYING PLEASE HELP ME IM SO SERIOUS IM GONNA END IT PLS
antiseptic1488 [7]

Answer:

\sf -11+7\sqrt{2}

Step-by-step explanation:

Given expression:

\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }

Rewrite 32 as 16 · 2:

\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }

Apply radical rule \sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }

As \sf \sqrt{16}=4:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} }

Multiply by the conjugate:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }

\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}

\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4\sqrt{2}\sqrt{2}}{1-\sqrt{2}+\sqrt{2}-\sqrt{2}\sqrt{2}}

As \sf \sqrt{2}\sqrt{2}=\sqrt{4}=2:

\sf \implies \dfrac{3-3\sqrt{2}-4\sqrt{2}+4 \cdot 2}{1-\sqrt{2}+\sqrt{2}-2}

\sf \implies \dfrac{3-7\sqrt{2}+8}{1-2}

\sf \implies \dfrac{11-7\sqrt{2}}{-1}

\sf \implies -11+7\sqrt{2}

7 0
2 years ago
Please help find the slope ​
kolbaska11 [484]
Graph plots and see where is curves
3 0
3 years ago
Find the distance between the points ?<br><br> ​
tatuchka [14]

Answer:

4

Step-by-step explanation:

The distance between the two points is (-1,-4) - (-5,-4)

5 0
3 years ago
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