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3 years ago

HELP ASAP PLZZ!! Drag the expressions into the boxes to correctly complete the table.

Mathematics

2 answers:

tino4ka555 [31]3 years ago

6 0

Drag the expressions into the boxes to correctly complete the table.

grandymaker [24]3 years ago

4 0

Polynomial:

x^3 - 4x - 3

-x^5 + 7x - 1/2x^2 + 9

x^4 + x^3 √7 + 2x^2 - √3/2x + π

Not a Polynomial:

x^4 + 5/x^3 - √x + 8

[x]^2 + 4√x - 2

4/x^2-4x+3

//hope this helped :)

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X · 1 + x/1 = _____.

mrs_skeptik [129]

First,

(x•1)+(x/1) = x+x

Then,

x+x=2x

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3 years ago

N is a integar Write the values of n such that -15<3n ≤6

Elena L [17]

Answer: -5 <n $\leq$ 2

Step-by-step explanation:

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3 years ago

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Lelechka [254]

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3 years ago

At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

MAXImum [283]

Answer-

At $x= \frac{1}{2304e^4-16e^2}$ the curve has maximum curvature.

Solution-

The formula for curvature =

$K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}$

Here,

$y=4e^{x}$

Then,

${y}' = 4e^{x} \ and \ {y}''=4e^{x}$

Putting the values,

$K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}$

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

${k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}$

Now, equating this to 0

$(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})$

$\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}$

$\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}$

$\Rightarrow 2304e^{2x}-16e^{2x}-1=0$

Solving this eq,

we get $x= \frac{1}{2304e^4-16e^2}$

∴ At $x= \frac{1}{2304e^4-16e^2}$ the curvature is maximum.

6 0

3 years ago

For the function Y=5x, what would happen if the value 5 was changed to 3

Daniel [21]

Answer:

y = 3 * x

Step-by-step explanation:

We have the function y = 5 * x, they ask us what would happen if we change the 5 by the 3. thus:

y = 3 * x

the constant that accompanies x in this case is an increase or slope constant, that is, now x will not increase by a ratio of 5, but by a ratio of 3. For example:

If x were worth 10

the value before was 50 and now it will be 30.

I do not increase 5 times but 3 times.

4 0

4 years ago