We are given with an isosceles triangle having a vertex on the curve given y =<span>27-x^2</span> .
The area of the triangle, A= xy = x (27-x^2)
A' = 27-x^2-2x^2 = 0
x = 3
Amax = 3(27-9) = 54 units2
<u>|4x + 2| + 6 = 0</u>
Subtract 6 from each side: |4x + 2| = -6
But the absolute value of a number is always positive.
No value of 'x' can ever make |4x + 2| negative.
So the equation has <em>no solution</em>.
Answer:
b, a, c
Step-by-step explanation:'
The side opposite of the smallest angle(50) is always the smallest, which means b is the smallest
Hope this helps!
Answer:
a: 3
b: 12
c: 15
Step-by-step explanation:
12 + 15 = 27
There are 27 total.
Since there are 27 in all, it's best if each small rectangle value is 3.
