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katrin2010 [14]
3 years ago
7

Question is on the picture

Mathematics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

12/5

Step-by-step explanation:

tan A = opp/adj

For angle theta, 12 is the opposite leg.

13 is the hypotenuse.

We were not given the length of the adjacent leg, but we can use the Pythagorean theorem to find it.

a^2 + b^2 = c^2

a^2 + 12^2 = 13^2

a^2 + 144 = 169

a^2 = 25

a = 25

The adjacent leg has a length of 5.

tan theta = opp/adj

tan theta = 12/5

Answer: 12/5

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Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.​

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

Hypotenuse^2=Base^2+Perpendicular^2

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

(9.85)^2=x^2+(x+5)^2

97.0225=x^2+x^2+10x+25

0=2x^2+10x+25-97.0225

0=2x^2+10x-72.0225

Here, a=2, b=10,c=-72.0225. Using the quadratic formula, we get

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}

x=\dfrac{-10\pm \sqrt{676.18}}{4}

Approximating the value, we get

x=\dfrac{-10\pm 26}{4}

x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}

x=\dfrac{16}{4},\dfrac{-36}{4}

x=4,-9

Distance cannot be negative so x\neq -9.

Now we have x=4

x+5=4+5

x+5=9

Therefore, the base is 4 m and the height is 9 m.

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SOA stands for

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Cosine Ф = adjacent side/hypotenuses side

Tangent Ф = opposite side/adjacent side

With respect to ∠B given that  ∠D=90°,

BD is the adjacent side

CB  is the hypotenuse side

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