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2 years ago

C an some one help me

Mathematics

1 answer:

Pavlova-9 [17]2 years ago

8 0

Answer:

Step-by-step explanation:

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Find the surface area of the rectangular prism. 3 cm 10 cm 7 cm [?] sq cm

Setler79 [48]

Answer:

Step-by-step explanation:

There are six faces on the prism:

Two faces are 7 cm by 10 cm, area = 7×10 = 70 cm² each

Two faces are 7 cm by 3 cm, area = 7×3 = 21 cm² each

Two faces are 10 cm by 3 cm, area = 10×3 = 30 cm² each

surface area = 2(70) + 2(21) + 2(30) = 140 + 42 + 60 = 242 cm²

5 0

2 years ago

PLEASE HELP HELPPPPPPO HELPPPPPPO

bezimeni [28]

Step-by-step explanation:

Remember that in a linear function of the form $f(x)=mx+b$ , $m$ is the slope and $b$ is the why intercept.

Part A. Since $g(x)=2x+6$ , its slope is 2 and its y-intercept is 6

Now, to find the slope of $f(x)$ we are using the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

where

$m$ is the slope

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

From the table the first point is (-1, -12) and the second point is (0, -6)

Replacing values:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-6--(12)}{0-(-1)}$

$m=\frac{-6+12}{0+1}$

$m=6$

The slope of f(x) is bigger than the slope of g(x), which means the line represented by f(x) is stepper than the line represented by g(x).

Part B. To find the y-intercept of f(x) we are taking advantage of the fact that the y-intercept of a linear function occurs when x = 0, so we just need to look in the table for the value of f(x) when x = 0. From the table $f(x)=-6$ when $x=0$ ; therefore the y-intercept of $f(x)$ is -6.

We already know that the y-intercept of g(x) is 2. Since 2 is bigger than -6, function g(x) has a greater y-intercept.

6 0

2 years ago

Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle

mario62 [17]

Step-by-step explanation:

The distance formula between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points.

$A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}$