All categories

2 years ago

PLEASE HELP WILL NAME BRAINLEST

Mathematics

1 answer:

Schach [20]2 years ago

7 0

Answer:

All of them are parallel

Step-by-step explanation:

This is due to the all of the 90 degree angle which would make the rest of the line a would be another 90 degree angle Which are found on every line. This would make all of the lines parallel because it is a total of 180 degrees.

You might be interested in

Factor this expression please

Orlov [11]

16x + 40y.....GCF is 8

8(2x + 5y) <==

5 0

3 years ago

Does anyone know the answer to both these questions ???

gavmur [86]

answer for 9 is 6cm not sure about 10

5 0

2 years ago

Sold 685 boxes of cookies about how many boxes are they sold rounded to the nearest ten

MissTica

Answer:

690

Step-by-step explanation:

Round from the tens place.

8 0

3 years ago

Round 32.697 to the nearest tenth hundredth and whole number

zalisa [80]

To the nearest tenth : 32.7

To the nearest hundredth : 32.70

Whole Number : 33

Hope this helps!

5 0

3 years ago

Please help me i need to find the area of shaded region please help me

Montano1993 [528]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=13\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)\\A=84-24\\A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)\\A=96-16\\A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)\\A=80+16\\A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)\\A=225-81\\A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(4)(2)\\A=21-8\\A=13\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)\\A=(49\pi -33)\ in^2$

6 0

3 years ago