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Citrus2011 [14]
3 years ago
8

Rewrite 15+(72+19)using the Associative Law of Addition.

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

(15+72)+19

Step-by-step explanation:

you get the same answer in the end bc all you have to do is rearrange the parentheses  

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Which of the following is a factor of 64x^3 +343
Lyrx [107]

Answer:

(4x + 7) or

(16x^2 - 28x + 49)

Step-by-step explanation:

This is the sum of cubes. If you have choices you really should list them because often the way  we write  answers is not in agreement with what you are given.

Step One

Factor 64x^3  and 343 into prime factors.

64x^3: 4*4*4*x * x *x

343: 7 * 7 * 7

Step Two

Factor using the sum of cubes.

(4x + 7)([4x]^2 - 7*4x + 7^2)

(4x + 7)(16x^2 - 28x + 49)


7 0
3 years ago
Read 2 more answers
David has scored 81 , 87 , 69 , and 82 on his previous four tests. what score does he need on his next test so that his average
kvv77 [185]
91 so the mean can avrege out to 82
7 0
2 years ago
Verify the identity by transforming the left-hand side into the right-hand side.
qaws [65]
<span>(1 + cos² 3θ) / (sin² 3θ) = 2 csc² 3θ - 1

Starting with the left:  Note that  cos²θ + </span><span>sin²θ = 1.
In the same way:    </span><span>cos²3θ + <span>sin²3θ = 1
</span></span>Therefore                cos²3θ  = 1 - <span>sin²3θ
</span> From the top:  (1 + cos² 3θ) = 1 + 1 - sin²3θ = 2 - <span>sin²3θ
</span>
(1 + cos² 3θ) / (sin² 3θ) = (<span>2 - sin²3θ) / (sin² 3θ) = 2/</span><span>sin² 3θ - </span><span>sin²3θ/</span>sin²3θ

=  2/<span>sin² 3θ - 1;        But 1/</span><span>sinθ = csc</span><span>θ,  Similarly  </span>1/sin3θ = csc3θ

= 2 *(1/sin<span>3θ)²  - 1</span>
= 2csc²3θ  - 1.        Therefore  LHS = RHS.  QED.

8 0
3 years ago
Help please I need it:
jonny [76]

Answer:

Step-by-step explanation:

The number of sandwiches sold: 73

The cost to make one sandwich: S

The profit the band earns from one sandwich: 0.2S

The amount of money that the band recieves for selling one sandwich:

S + 0.2S

6 0
2 years ago
Read the following numbers and write them in expanded form 443 092 101<br>​
max2010maxim [7]
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