P(A) = P(8) + P(9) + P(10) = 3/10 so P(A complement) = 1 - P(A) = 1 - 3/10 = 7/10 - D
ANSWER = 154^3+10^2+12+15
Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."
2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8. Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."
54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.
Answer:
Part A: Data summary is given in the table
Part B: out of the total 100 students, 15 students do not like either tennis or track
= 0.15
0.15 × 
= 15%
Part C:
Total no. of students that dislike track = 60
Total no. of students that dislike tennis = 40
According to the survey results, more people dislike track.
