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ivann1987 [24]
3 years ago
7

Find the height of the triangle in which A=192 cm^2

Mathematics
1 answer:
romanna [79]3 years ago
6 0

Step-by-step explanation:

one second 12345678910

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LekaFEV [45]

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16 the answer

Step-by-step explanation:

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3 years ago
using the coordinate plane shown below 1/3 point is plotted five units to the right of -4, for where should a four point be plan
Mrac [35]

we know that

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so

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the y-coordinate of the fourth point is the same y coordinate of (-4,4)

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3 years ago
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RUDIKE [14]

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2 years ago
A The length of a rectangle is 4 m more
Lady bird [3.3K]

Given :

  • The length of a rectangle is 4m more than the width.
  • The area of the rectangle is 45m²

⠀

To Find :

  • The length and width of the rectangle.

⠀

Solution :

We know that,

\qquad { \pmb{ \bf{Length \times Width = Area_{(rectangle)}}}}\:

So,

Let's assume the length of the rectangle as x and the width will be (x – 4).

⠀

Now, Substituting the given values in the formula :

\qquad \sf \: { \dashrightarrow x  \times  (x - 4) = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x = 45 }

\qquad \sf \: { \dashrightarrow {x}^{2}  - 4x - 45 = 0 }

\qquad \sf \: { \dashrightarrow {x}^{2}    - 9x+ 5 x - 45 = 0 }

\qquad \sf \: { \dashrightarrow x(x - 9) + 5(x - 9) = 0 }

\qquad \sf \: { \dashrightarrow (x  - 9) (x  + 5) = 0 }

\qquad \sf \: { \dashrightarrow x = 9, \: \: x =  - 5}

⠀

Since, The length can't be negative, so the length will be 9 which is positive.

⠀

\qquad { \pmb{ \bf{ Length _{(rectangle)} = 9\:m}}}\:

\qquad { \pmb{ \bf{ Width _{(rectangle)} = 9 - 4=5\: m}}}\:

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

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