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ankoles [38]
3 years ago
11

Can someone please help me with this question​

Mathematics
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

16 the answer

Step-by-step explanation:

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Suppose the half-life of a material is 10 days. You have one 1 kg of the material today. How much of the material would you have
boyakko [2]

Answer:

0.50 kg of the material would be left after 10 days.

0.25 kg of the material would be left after 20 days.

Step-by-step explanation:

We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after  10 days and 20 days, respectively.

We will use half life formula.

A=a\cdot(\frac{1}{2})^{\frac{t}{h}}, where,

A = Amount left after t units of time,

a = Initial amount,

t = Time,

h = Half-life.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{10}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{1}

A=1\text{ kg}\cdot\frac{1}{2}

A=0.5\text{ kg}

Therefore, amount of the material left after 10 days would be 0.5 kg.

A=1\text{ kg}\cdot(\frac{1}{2})^{\frac{20}{10}}

A=1\text{ kg}\cdot(\frac{1}{2})^{2}

A=1\text{ kg}\cdot\frac{1^2}{2^2}

A=1\text{ kg}\cdot\frac{1}{4}

A=0.25\text{ kg}

Therefore, amount of the material left after 20 days would be 0.25 kg.

6 0
3 years ago
Please help me solve this word problem please
leonid [27]

Answer:

it is 69

Step-by-step explanation:

do calculations

8 0
3 years ago
Inscribed circles on the arc; improvement answer is required in full.
e-lub [12.9K]

Answer:

The measure of an inscribed angle is half the measure of the intercepted arc

∠EFG creates Arc EDG

if ∠EFG is 1/2 arc EDG then 115° x 2 = 230°

A circle is 360°.

The remaining arc EFG is 360° - 230° = 130°

∠EDG is 1/2 of arc EFG so, 130° ÷ 2 = 65°

∠EDG = 65°

8 0
3 years ago
What is sin 0 when sec 0 = 5? 0 |(1,0) sin e = 2[?] [] Rationalize the denominator if necessary.​
Komok [63]

Answer:

Sin ~0 =\frac{2\sqrt{5} }{5}

Step-by-step explanation:

sec0=\sqrt{5}

cos~0=\frac{1}{sec0} =\frac{1}{\sqrt{5} }

sin ~0=\sqrt{1-cos^2~0}

=\sqrt{1-1/5}=\sqrt{5-1/5}

Sin~0=\sqrt{4/5} =2/\sqrt{5}*\sqrt{5}/\sqrt{5}

Sin~0=2\sqrt{5}/2=2\sqrt{5}/5

<u>--------------------------------</u>

hope it helps...

have a great day!!!

7 0
3 years ago
PLEASE HELP ME OUT WITH MATH!
Helen [10]

Answer:

C

Step-by-step explanation:

If you multiply it out it looks like

7/1 times 1/8

multiply across (7 times 1 / 1 times 8)

gives you 7/8

7 0
2 years ago
Read 2 more answers
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