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katrin [286]
3 years ago
9

HELP ME THIS THE LAST ONE AND THEN I AM DONE PLS HELP BTW I COULDN’T TAP ON THE LINK THAT U GAVE ME I FORGOT UR NAME

Mathematics
1 answer:
Iteru [2.4K]3 years ago
3 0

Answer:

\Huge\boxed{V=550}

Step-by-step explanation:

Hello There!

For this problem we want to split the irregular 3d figure into two regular 3d figures

Two rectangular prisms with the following dimensions

rectangular prism 1

length - 5 feet

width - 12 feet

height - 5 feet

rectangular prism 2

length - 5 feet

width - 5 feet

height - 10 feet (was found by subtract height of rectangular prism 1 (5 feet) from the total height of the irregular figure (15-5=10 so the height of rectangular prism 2 is 10 feet)

Now to find the volume of each individual prism...

So remember the formula for volume of a rectangular prism is

volume = length x width x height

so having the dimensions of each rectangular prism we plug in each value to the formula ( remember we're doing this for each individual rectangular prism)

For rectangular prism 1

V = 12 x 5 x 5

12x5x5=300 so the volume of rectangular prism is 300 cubic feet

For rectangular prism 2

V = 10 x 5 x 5

10x5x5=250 so the volume of rectangular prism is 250 cubic feet

our final step is to add the two volumes together

250 + 300 = 550

so we can conclude that the volume of the rooftop is 550

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The diagram shows a right triangle and three squares. The area of the largest square is 55 units.
Keith_Richards [23]

Answer:

A

B

C

Step-by-step explanation:

Well the sides of the smaller squares have to be greater than the biggest when put together.

a + b > c

So we need to find the square root of 55.

\sqrt{55}

≅ <u>7.4</u>

<u />

Now for option A)

srt ⇒ 12 ≅3.5

srt ⇒ 43 ≅ 6.6

3.5 + 6.6 = <u>10.1</u>

So option A is correct.

Option B)

srt ⇒ 14 ≅ 3.7

srt ⇒ 40 ≅ 6.3

3.7 + 6.3 = <u>10</u>

So option B is also correct.

Option C)

srt ⇒ 16 = 4

srt ⇒ 37 ≅ 6.1

4 + 6.1 = <u>10.1</u>

So option C is also correct.

<em>Therefore,</em>

<em>all options are correct.</em>

<em />

<em>Hope this helps :)</em>

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