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Sliva [168]
3 years ago
8

I hate this!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0

Answer:

Same!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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Dan earns £9.90 per hour. How much will he earn for 4 hours work?
Natasha2012 [34]

Answer:

39.60

Step-by-step explanation:

9.90 x 4 = 39.60

8 0
3 years ago
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Hayden lives in Jefferson City, MO, which has a population of 48, 838. He says Kansas City's population is about
ladessa [460]

Answer:

the awser is d if you round it up

Step-by-step explanation:

8 0
3 years ago
PLEASE HELP IN MATH . ( PLEASE GIVE EXPLANATION )<br> 5 EASY POINTS
Black_prince [1.1K]
The answer is "Design B bulbs will likely last longer than design A bulbs."

The box in a box plot represents the middle 50% of the data. The box for the design B bulbs is farther out than the box for the design A bulbs. Therefore, design B bulbs last longer on average than design A bulbs.
7 0
3 years ago
4 cm on a map are equal to 6 km in real life. if two points are 16 cm apart on the map, how far apart are they in real life
Maksim231197 [3]

Answer:

24km

Step-by-step explanation:

16/4 is 4 so you multiply that by 6 and you get 24. the equation is (16/4)*6

6 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
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