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maw [93]
2 years ago
7

Which number line represents the solution set for the inequality –4(x + 3) ≤ –2 – 2x?

Mathematics
2 answers:
andrew-mc [135]2 years ago
7 0
The answer is> -5.....
const2013 [10]2 years ago
4 0
-4(x + 3) < = -2 - 2x
-4x - 12 < = -2 - 2x
-4x + 2x < = -2 + 12
-2x < = 10
x > = -5

the correct number line will have closed circle on -5 with shading to the right
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Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the game
Sunny_sXe [5.5K]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

Eric and Joshua are playing ping pong and pool. Joshua believes he has a good chance of beating Eric in at least one of the games. The probability Joshua beats Eric in ping pong is 0.48. The probability Joshua beats Eric in pool is 0.46. Joshua is willing to assume the probability of Eric winning a game of ping pong is independent of him winning a game of pool.

Find the probability:

The probability that Joshua beats Eric in ping pong AND pool?

The probability that Joshua beats Eric in ping pong OR pool?

Answer:

P(pp & pool) = 22%

There is 22% probability that Joshua beats Eric in ping pong AND pool.

P(pp OR pool) = 50%

There is 50% probability that Joshua beats Eric in ping pong OR pool.

Step-by-step explanation:

The probability Joshua beats Eric in ping pong is given by

P(pp) = 0.48

The probability Joshua beats Eric in pool is given by

P(pool) = 0.46

The probability that Joshua beats Eric in ping pong AND pool is given by

P(pp & pool) = P(pp)×P(pool)

P(pp & pool) = 0.48×0.46

P(pp & pool) = 0.22

P(pp & pool) = 22%

Therefore, there is 22% probability that Joshua beats Eric in ping pong AND pool.

The probability that Joshua beats Eric in ping pong OR pool is given by

P(pp OR pool) = P(pp)×0.52 + P(pool)×0.54

Where 0.52 is the probability that Eric beats Joshua in the ping pong match (1 - 0.48 = 0.52)

Where 0.54 is the probability that Eric beats Joshua in the pool match (1 - 0.46 = 0.54)

P(pp OR pool) = 0.48×0.52 + 0.46×0.54

P(pp OR pool) = 0.25 + 0.25

P(pp OR pool) = 0.50

P(pp OR pool) = 50%

Therefore, there is 50% probability that Joshua beats Eric in ping pong OR pool.

6 0
3 years ago
B) Which one of the following points lies on the line 2y = 5x - 3?
sergeinik [125]
Given the equation 2y = 5x - 3:

A way to find out which of the ordered pair options lie on the line is to substitute their coordinates into the equation.


A) (2, 5)
2y = 5x - 3
2(5) = 5(2) - 3
10 = 10 - 3
10 = 7 (False statement). this means that (2, 5) is not a solution to the given equation.

B) (6, 3)
2y = 5x - 3
2(3) = 5(6) - 3
6 = 30 - 3
6 = 27 (False statement). this means that (6, 3) is not a solution to the given equation.

C) (3, -6)
2y = 5x - 3
2(-6) = 5(3) - 3
-12 = 15 - 3
-12 = 12 (False statement). this means that (3, -6) is not a solution to the given equation.

D) (3, 6)
2y = 5x - 3
2(6) = 5(3) -3
12 = 15 - 3
12 = 12 (True statement). This means that (3, 6) IS a solution to the given equation.

E) (2, -5)
2y = 5x - 3
2(-5) = 5(2) - 3
-10 = 10 - 3
-10 = 7 (False statement). this means that (2, -5) is not a solution to the given equation.

Therefore, the correct answer is Option D: (3, 6).
7 0
2 years ago
Michael pays $30 to enter a state fair, plus $4 for each ride. Which of the following equations represents his total cost? A. y=
omeli [17]
He spends 30 to enter and 4 per ride

y = 4x + 30....with x being the number of rides and y being the total cost
4 0
3 years ago
Read 2 more answers
Abby, Bernardo, Carl, and Debra play a game in which each of them starts with four coins. The game consists of four rounds. In e
Sedaia [141]

The probability that, at the tip of the fourth round, each of the players has four coins is 5/192.

Given that game consists of 4 rounds and every round, four balls are placed in an urn one green, one red, and two white.

It amounts to filling in an exceedingly 4×4 matrix. Columns C₁-C₄ are random draws each round; row of every player.

Also, let \%R_{A} be the quantity of nonzero elements in R_{A}.

Let C_{1}=\left(\begin{array}{l}1\\ -1\\ 0\\ 0\end{array}\right).

Parity demands that \%R_{A} and\%R_{B} must equal 2 or 4.

Case 1: \%R_{A}=4 and \%R_B=4. There are \left(\begin{array}{l}3\\ 2\end{array}\right)=3 ways to put 2-1's in R_A, so there are 3 ways.

Case 2: \%R_{A}=2 and \%R_B=4. There are 3 ways to position the -1 in R_A, 2 ways to put the remaining -1 in R_B (just don't put it under the -1 on top of it!), and a pair of ways for one among the opposite two players to draw the green ball. (We know it's green because Bernardo drew the red one.) we are able to just double to hide the case of \%R_{A}=4,\%R_{B}=2 for a complete of 24 ways.

Case 3: \%R_A=\%R_B=2. There are 3 ways to put the -1 in R_{A}. Now, there are two cases on what happens next.

  • The 1 in R_B goes directly under the -1 inR_A. There's obviously 1 way for that to happen. Then, there are 2 ways to permute the 2 pairs of 1,-1 in R_C andR_D. (Either the 1 comes first inR_C or the 1 comes first in R_D.)
  • The 1 in R_B doesn't go directly under the -1 in R_A. There are 2 ways to put the 1, and a couple of ways to try and do the identical permutation as within the above case.

Hence, there are 3(2+2×2)=18 ways for this case. There's a grand total of 45 ways for this to happen, together with 12³ total cases. The probability we're soliciting for is thus 45/(12³)=5/192

Hence, at the top of the fourth round, each of the players has four coins probability is 5/192.

Learn more about probability and combination is brainly.com/question/3435109

#SPJ4

3 0
2 years ago
Read 2 more answers
Why would my teacher give me a math paper on something I didn't learn yet? Is she okay?
luda_lava [24]

Answer:

your teacher is crazy about she think you are smart

5 0
2 years ago
Read 2 more answers
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