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3 years ago

The _____ class can be used to get user input using dialog boxes.

Computers and Technology

1 answer:

Ber [7]3 years ago

4 0

Answer:

JOptionPane

Explanation:

The class "JOptionPane" are used to pop / create dialogue boxes for the user to enter the input for a question.
JOptionPane contains methods to create input dialogue boxes, message dialogue boxes, option dialogue boxes and confirm dialogue boxes.
The dialogue boxes can be just message dialogue boxes which gives some message to the user. It doesn't require anything to be input from the user. It is just a message box.
Where as input dialogue box requires the user to input something.
Confirm dialogue box asks the user to answer a question yes / no / cancel.
Option dialogue box asks the user to select the options.
So, option (d) JOptionPane is the answer for the question.
Option (a), (b) and (c) are used for different purposes but not to create dialogue boxes. So, options (a), (b) and (c) are not the correct answers for the question.

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A student who used a regression model that included indicator variables was upset when receiving only the following output on th

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Answer:

This is a multicolinearity problem and the student should determine the variable(s) that cause(s) the problem and remove it.

Explanation:

This information means that there exists a linear combination between the independent variables. The problem might have developed due to multicolinearity producing almost perfectly linearly dependent columns.

This could also be as a results of single matrix created when the student use an incorrect indicator variables and included an additional indicator column which created linearly dependent columns.

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3 years ago

According to the presentation, integrity and ethics are particularly important for careers in which of the following pathways?

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3 years ago

Show the array that results from the following sequence of key insertions using a hashing system under the given conditions: 5,

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Answer:

a) Linear probing is one of the hashing technique in which we insert values into the hash table indexes based on hash value.

Hash value of key can be calculated as :

H(key) = key % size ;

Here H(key) is the index where the value of key is stored in hash table.

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Given,

Keys to be inserted are : 5 , 205, 406,5205, 8205 ,307

and size of the array : 100.

First key to be inserted is : 5

So, H(5) = 5%100 = 5,

So, key 5 is inserted at 5th index of hash table.

-----

Next key to inserted is : 205

So, H(205) = 205%100 = 5 (here collision happens)

Recompute hash value as follows:

H(key) =(key+i) % size here i= 1,2,3...

So, H(205) =( 205+1)%100 = 206%100 = 6

So, key 205 is inserted in the 6th index of the hash table.

----------

Next Key to be inserted : 406

H(406) = 406%100 = 6(collision occurs)

H(406) =(406+1) %100 = 407%100 = 7

So, the value 406 is inserted in 7the index of the hash table.

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Next key : 5205

H(5205) = 5205%100 = 5(collision)

So, H(5205) = (5205+1)%100 = 6( again collision)

So, H(5205) = 5205+2)%100 = 7(again collision)

So, H(5205) = (5205+3)%100 = 8 ( no collision)

So, value 5205 is inserted at 8th index of the hash table.

-------------

Similarly 8205 is inserted at 9th index of the hash table because , we have collisions from 5th to 8th indexes.

-------------

Next key value is : 307

H(307) = 307%100 = 7(collision)

So, (307+3)%100 = 310%100 = 10(no collision)

So, 307 is inserted at 10th index of the hash table.

So, hash table will look like this:

Key index

5 5

205 6

406 7

5205 8

8205 9

307 10

b) Quadratic probing:

Quadratic probing is also similar to linear probing but the difference is in collision resolution. In linear probing in case of collision we use : H(key) = (key+i)%size but here we use H(key) =( key+i^2)%size.

Applying Quadratic probing on above keys:.

First key to be inserted : 5.

5 will go to index 5 of the hash table.

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Next key = 205 .

H(205) = 205%100 = 5(collision)

So. H(key)= (205+1^2)%100 = 6(no collision)

So, 205 is inserted into 6th index of the hash table.

--------

Next key to be inserted 406:

So, 406 %100 = 6 (collision)

(406+1^2)%100 = 7(no collision)

So, 406 is moved to 7th index of the hash table.

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Next key is : 5205

So, 5205%100 = 5 (collision)

So, (5205+1^2)%100 = 6 ( again collision)

So, (5205+2^2)%100 = 9 ( no collision)

So, 5205 inserted into 9th index of hash table.

-----------

Next key is 8205:

Here collision happens at 5the , 6the , 9th indexes,

So H(8205) = (8205+4^2)%100 = 8221%100 = 21

So, value 8205 is inserted in 21st index of hash table.

--------

Next value is 307.

Here there is collision at 7the index.

So, H(307) = (307+1^2)%100 = 308%100= 8.

So, 307 is inserted at 8the index of the hash table.

Key Index

5 5

205 6

406 7

5205 9

8205 21

307 8

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