3 years ago

Rewrite the set M by listing its elements. Make sure to use the appropriate set notation

1 answer:

8 0

We are given the rule for the set,
M= {x | x is an integer and -2 < x < 1}In words, this set translates to numbers that are integers and greater than -2 but less than 1.
The actual elements of the set are
M = { -1, 0}
There are only two elements.

You might be interested in

Solve. -13-8a-4a=-3

bezimeni [28]

-13-8a-4a=-3+13

-8a-4a=10

-12a=10

10/-12=a

a= -0.83

8 0

3 years ago

Read 2 more answers

12.917 rounded to the nearest ones

adelina 88 [10]

I am pretty sure the answer is 13

6 0

3 years ago

Read 2 more answers

A 19% discount on a watch saved a shopper $76 . find the price of the watch before the discount

Alik [6]

The watch costed $400 before the discount.

76 * 100 = 7,600
7,600 / 19 = 400

3 0

3 years ago

Use the Pythagorean Theorem to determine which of the following give the measures of the legs and hypotenuse of a right triangle

kakasveta [241]

The Pythagorean theorem states that the square of the hypotenuse is equal to the sum of the squares of the legs:

$c^2=a^2+b^2.$

The hypotenuse is the side with the greatest length.

Check all options:

1. c=5, a=3, b=4:

$5^2=25,\\3^2+4^2=9+16=25,\\5^2=3^2+4^2$ true.

2. c=14, a=4, b=11:

$14^2=196,\\4^2+11^2=16+121=137,\\14^2\neq 4^2+11^2$ false.

3. c=17, a=9, b=14:

$17^2=289,\\9^2+14^2=81+196=277,\\17^2\neq 9^2+14^2$ false.

4. c=16, a=8, b=14:

$16^2=256,\\8^2+14^2=64+196=260,\\16^2\neq 8^2+14^2$ false.

5. c=17, a=8, b=15:

$17^2=289,\\8^2+15^2=64+225=289,\\17^2=8^2+15^2$ true.

Answer: correct options are A and E.

4 0

3 years ago

Read 2 more answers

How do you create a restriction for √z + 8=13 ?

Zinaida [17]

√z = 13 - 8
√z = 5
z = 5²
z = 25
In this case the z can be any number, however z cannot be less than 0 and that is the restriction. (for example; √-1 = irrational number, cannot be solved.)

6 0

3 years ago

Read 2 more answers