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kari74 [83]
3 years ago
5

What number do you get when you decrease the ones digit of 2019 by 2?

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0
2019-2=2017

Since 9 is the ones digit 9-2=7
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What is 1 2/3 as an improper fraction
nataly862011 [7]
Hi there! To turn a mixed number into a improper fraction we multiply 1 by 3 and add 2. 1 2/3=1×3+2/3=5/3. Therefore, 1 2/3 as an improper fraction is 5/3.
6 0
4 years ago
What is the coefficient of x2y3 in the expansion of (2x + y)5?
Zigmanuir [339]

Option C:

The coefficient of x^{2} y^{3} is 40.

Solution:

Given expression:

(2 x+y)^{5}

Using binomial theorem:

(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}

Here a=2 x, b=y

Substitute in the binomial formula, we get

(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}

                                                            $+\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}+\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}

Let us solve the term one by one.

$\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}=32 x^{5}

$\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1} = 80 x^{4} y

$\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}= 80 x^{3} y^{2}

$\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}= 40 x^{2} y^{3}

$\frac{5 !}{4 !(5-4) !}(2 x)^{1} y^{4}= 10 x y^{4}

$\frac{5 !}{5 !(5-5) !}(2 x)^{0} y^{5}=y^{5}

Substitute these into the above expansion.

(2x+y)^5=32 x^{5}+80 x^{4} y+80 x^{3} y^{2}+40 x^{2} y^{3}+10 x y^{4}+y^{5}

The coefficient of x^{2} y^{3} is 40.

Option C is the correct answer.

5 0
3 years ago
Giải pt sin(x^2-4x)=0
Ivenika [448]

Answer:

x=0,2half1?(I'm

not sure)

3 0
3 years ago
Hi please help,i really need it and so appreciate it:)
nadya68 [22]

Hey there!

12 ≥ 5f - 18

5f - 18 ≤ 12

ADD 18 to BOTH SIDES

5f - 18 + 18 ≤ 12 + 18

SIMPLIFY IT!

5f ≤ 30


DIVIDE 5 to BOTH SIDES

5f/5 ≤ 30/5


SIMPLIFY IT!

f ≤ 6


Therefore, your answer is: f ≤ 6


Good luck on your assignment & enjoy your day!




~Amphitrite1040:)

7 0
2 years ago
CAN SOME ACTUALLY HELP ME PLEASE!!!!!!!!!!!!!!!!!!
Ahat [919]

Answer:

(1, No, No) (2, No, Yes) (3,  6x^2+10) (4, 2x^2-3) (5,  x^2-x) (6, -2x^4+12x+3)

(7,  3x^3+15x^2+20)  (8, 9x^3 + 4x^2+8x)  (9, xy+2x+6y+5) Sorry didn't have an answer for 10. I hope they are all correct sorry for the wait.

Step-by-step explanation:

6 0
3 years ago
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