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kari74 [83]
3 years ago
5

What number do you get when you decrease the ones digit of 2019 by 2?

Mathematics
1 answer:
Luba_88 [7]3 years ago
6 0
2019-2=2017

Since 9 is the ones digit 9-2=7
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Help! Best answer gets branliest!
kykrilka [37]
I believe you multiply all sides to get the area and you add all sides to get the perimeter.
7 0
3 years ago
How could the formula for perimeter be rearranged to find the length of the playground?
Gennadij [26K]
P = 2l + 2w
p - 2w = 2l
l = p-2w/2
It would be the third response
6 0
3 years ago
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Bob and mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum
taurus [48]
I can only give possible combinations of the ages. This is because only the product is given. Had the sum of all ages been given, possible combinations would boil down into 1 combination.

3 kids with a youngest. This means that the ages are not the same.
We do prime factorization to get the age combination.

72 ÷ 2 = 36
36 ÷ 2 = 18
18 ÷ 2 =   9
  9 ÷ 3 =   3
  3 ÷ 3 =   1

1 x 2 x 2 x 2 x 3 x 3 = 72

Possible combination with no repeating number.

1 x 8 x 9 = 72
2 x 4 x 9 = 72
4 x 6 x 3 = 72
1 x 6 x 12 = 72
4 0
3 years ago
How do you get an equation to solve for all 3 sides of a triangle?
slavikrds [6]

In your solving toolbox (along with your pen, paper and calculator) you have these 3 equations:

1. The angles always add to 180°:

A + B + C = 180°

When you know two angles you can find the third.

 

2. Law of Sines (the Sine Rule):

Law of Sines

When there is an angle opposite a side, this equation comes to the rescue.

Note: angle A is opposite side a, B is opposite b, and C is opposite c.

 

3. Law of Cosines (the Cosine Rule):

Law of Cosines

This is the hardest to use (and remember) but it is sometimes needed  

to get you out of difficult situations.

It is an enhanced version of the Pythagoras Theorem that works  

on any triangle.

With those three equations you can solve any triangle (if it can be solved at all).

Six Different Types (More Detail)

There are SIX different types of puzzles you may need to solve. Get familiar with them:

1. AAA:

This means we are given all three angles of a triangle, but no sides.

AAA Triangle

AAA triangles are impossible to solve further since there are is nothing to show us size ... we know the shape but not how big it is.

We need to know at least one side to go further. See Solving "AAA" Triangles .

 

2. AAS

This mean we are given two angles of a triangle and one side, which is not the side adjacent to the two given angles.

AAS Triangle

Such a triangle can be solved by using Angles of a Triangle to find the other angle, and The Law of Sines to find each of the other two sides. See Solving "AAS" Triangles.

 

3. ASA

This means we are given two angles of a triangle and one side, which is the side adjacent to the two given angles.

ASA Triangle

In this case we find the third angle by using Angles of a Triangle, then use The Law of Sines to find each of the other two sides. See Solving "ASA" Triangles .

 

4. SAS

This means we are given two sides and the included angle.

SAS Triangle

For this type of triangle, we must use The Law of Cosines first to calculate the third side of the triangle; then we can use The Law of Sines to find one of the other two angles, and finally use Angles of a Triangle to find the last angle. See Solving "SAS" Triangles .

 

5. SSA

This means we are given two sides and one angle that is not the included angle.

SSA Triangle

In this case, use The Law of Sines first to find either one of the other two angles, then use Angles of a Triangle to find the third angle, then The Law of Sines again to find the final side. See Solving "SSA" Triangles .

 

6. SSS

This means we are given all three sides of a triangle, but no angles.

SSS Triangle

In this case, we have no choice. We must use The Law of Cosines first to find any one of the three angles, then we can use The Law of Sines (or use The Law of Cosines again) to find a second angle, and finally Angles of a Triangle to find the third angle.

7 0
3 years ago
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The value of a car decreases $500 for every 1,000 miles it is driven. The current value of the car is $23,000, and the car is dr
Hoochie [10]

Answer: C

Step-by-step explanation:

If we know the value of the car decreases $500 for every 1,000 miles, and that the car is driven about 10,000 miles every year, that means that you need to take the total value of the car (23,000) and subtract it from the amount of money it is losing per year. Again, the car is driven about 10,000 miles per year, so that means that the car will most likely continue to be driven 10,000 miles per year. If you do the math, for one year, the value of the car will drop $5,000 ($500 x 10, because it is $500 per every 1,000 miles) So, for each year, you can just multiply the number of years by $5,000 to find out how much the vehicle has depreciated over time.

Hope this helped you and made sense! Feel free to ask me any questions you have!

4 0
3 years ago
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