Difference of 2 perfec squares is
(a^2)-(b^2)
if the exponents are both even and the coeficient (the number in front) are perfect squares, then it is difference t 2 perfect squares
first one
8 is not perfect square
2nd one
(4e^4)^2-(9g^2)^2
third
25 is odd, so it cannot be split up into 2 nice numbers
4th
(11m^9)^2-(3n^5)^2
Answer:
8/9 of the course are males.
Answer:
5. 26⁰F, rise
6. 0, Added both the numbers instead of subtracting
7. 10⁰C
8. 25⁰F
9. 13⁰F
10. -4
Answer:
0≥x<4
Step-by-step explanation:
first, let's look at this number line.
there is a closed circle at 0 and an open circle at 4. this means that 0 is included (≤ or ≥) and that 4 is not included (< or >).
these are the endpoints, meaning that in this compound inequality, the numbers next to the symbols are 0 and 4.
x is in the middle of this compound inequality.
0 x 4
now, we have to figure out the symbols in between. i wrote out our choices above for each number. the highlighted portion is greater than or equal to 0 and less than 4, so we can write this compound inequality as the following:
0≥x<4
x is greater than or equal to 0, but less than 4
Answer:
Angle A = 53
Step-by-step explanation:
All triangles add up to 180 so...
Lets use x to describe angle A
100+27+x=180
127+x=180
x=53
I'm confused what its asking about b and c but hope this helps a bit :)
