Answer: 12
Step-by-step explanation:
Let w = the width of the rectangle
Let 2w = the length
P = 2l + 2w
36 = 2(2w) + 2w
36 = 4w + 2w
36 = 6w
w = 6
l = 2(6)
l = 12
Answer:
± 27.33 ft
Step-by-step explanation:
For the given problem, we can estimate the initial and final coordinates of the line of the ball path as (-40,-50) and (0,0). Therefore, the slope is:
(-50-0)/(-40-0) = 50/40 = 1.25
Similarly, we can estimate the slope of a perpendicular line to the line of the ball path as: -1*(1/1.25) = -0.8.
Therefore, using (0,0) and the slope -0.8, the equation of the perpendicular line is: -0.8 = (y-0)/(x-0);
-0.8 = y/x
y = -0.8x
Furthermore, we are given the circle radius as 35 ft and we can use the distance formula to find the two points 35 ft far from the origin:
35^2 = x^2 + y^2
y = -0.8x
35^2 = x^2 + (-0.8x)^2
1225 = (x^2 + 0.64x^2)
1225 = 1.64x^2
x^2 = 1225/1.64 = 746.95
x = sqrt(746.95) = ± 27.33 ft
the answers are B,D and F
Answer:
6 ft/min
Step-by-step explanation:
Theres a neat trick to note; whenever you say per think of it as a fancy word for divide, because the label is always gonna be a/b (a per b)
Therefore,
the rate of feet per minute will be the feet divided by the minutes;
18 feet in 3 minutes = <u>18</u>/3 <u>ft</u>/min
Therefore the rate is 6 feet per minute.
<u>IF you need an explanation on what average rate implies:</u>
<em>Note; the word average is not prudent to answer as its extraneous, however if there was more data like "Cami descends 18 ft in 3 min and Nami descends 9 ft in 3 minutes; whats the average rate at which they descend" then you'd have to add the two rates up and divide by two.</em>
Hope this helps :)
F(x)=x/6+2
There is no restriction upon the values of x, or the values of y.
So the domain and range are both the set of all real numbers.
x=(-oo, +oo) and y=(-oo, +oo)
This can be further seen by the fact that this is a line with a slope of 1/6. So there is no restriction upon x as all values of x produce real values of y. And y approaches -oo as x approaches -oo and y approaches +oo as x approaches +oo.
