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3 years ago

Work the following pricing problems for services rendered. (Round to tenths.)

Mathematics

2 answers:

Pie3 years ago

8 0

Answer:

Overhead rate = $6.3

Step-by-step explanation:

Given : Labor rate = $8.00 per hour

Labor time = 6 hours

Retail price of parts = $0

Total job cost = $86.00

To find : Overhead rate

Solution:

Overhead cost = Total Cost - The cost of all inputs

The Overhead Rate is this number divided by total labor hours.

Total job cost = $86.00

Labor Cost = labor rate × labor time = 8 × 6 = $48

Retail price of parts:$0

Overhead Costs = total cost - labor cost= $86 - $48 = $38

Now, we divided overhead cost by labor hours to get overhead rate,

Overhead Rate $=\frac{38}{6}=6.33$

Therefore, Overhead rate is $6.3

AnnyKZ [126]3 years ago

5 0

8*6=48

86/8=10.80 (rounded)

so 48*10.80=518.40

the overhead rate was $518.40

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Mary brought $20 to the skating rink. She paid $5.50 admission and $3.75 to rent skates. She also purchased two bottles of water

Salsk061 [2.6K]

Answer:

20-14.5=5.5

Step-by-step explanation:

7 0

3 years ago

Y= y 48 Helppppp angle sum theorem

solmaris [256]

Answer:

Step-by-step explanation:

180-(48+90)=y

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4 0

3 years ago

The circumference of a circle is 60π cm. What is the radius of the circle

Sindrei [870]

Answer:

15 cm

Step-by-step explanation:

Circumference of circle= 2πr, where r us the radius of the circle.

Given that the circumference of circle is 60πcm,

60π= 2πr

Divide by 2 on both sides,

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Divide by π on both sides,

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Thus, radius of circle= 15cm.

8 0

4 years ago

If sinx = p and cosx = 4, work out the following forms :

Kay [80]

Answer:

$\frac{p^2 - 16} {4p^2 + 16}$

Step-by-step explanation:

I will work with radians.

$\frac {\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)} {[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]}$

First, I will deal with the numerator

$\cos^2 \left(\frac{\pi}{2}-x \right)+\sin(-x)-\sin^2 \left(\frac{\pi}{2}-x \right)+\cos \left(\frac{\pi}{2}-x \right)$

Consider the following trigonometric identities:

$\boxed{\cos\left(\frac{\pi}{2}-x \right)=\sin(x)}$

$\boxed{\sin\left(\frac{\pi}{2}-x \right)=\cos(x)}$

$\boxed{\sin(-x)=-\sin(x)}$

$\boxed{\cos(-x)=\cos(x)}$

Therefore, the numerator will be

$\sin^2(x)-\sin(x)-\cos^2(x)+\sin(x) \implies \sin^2(x)- \cos^2(x)$

Once

$\sin(x)=p$

$\cos(x)=4$

$\sin^2(x)-\cos^2(x) \implies p^2-4^2 \implies \boxed{p^2-16}$

Now let's deal with the numerator

$[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)]$

Using the sum and difference identities:

$\boxed{\sin(a \pm b)=\sin(a) \cos(b) \pm \cos(a)\sin(b)}$

$\boxed{\cos(a \pm b)=\cos(a) \cos(b) \mp \sin(a)\sin(b)}$

$\sin(\pi -x) = \sin(x)$

$\sin(2\pi +x)=\sin(x)$

$\cos(2\pi-x)=\cos(x)$

Therefore,

$[\sin(\pi -x)+\cos(-x)] \cdot [\sin(2\pi +x)\cos(2\pi-x)] \implies [\sin(x)+\cos(x)] \cdot [\sin(x)\cos(x)]$

$\implies [p+4] \cdot [p \cdot 4]=4p^2+16p$

The final expression will be

$\frac{p^2 - 16} {4p^2 + 16}$

8 0

3 years ago

If 60% of the students in your class like Burger King, how many students are in your class if 15 students like Burger King?

zloy xaker [14]

Answer:

Step-by-step explanation:

Let x be the number of students in the class

15 is 60% of x

60% of x can be written as 0.6x

15 = 0.6x

Divide by 0.6 on both sides

25 = x

There are 25 students in the class

Hope this helps :)

8 0

2 years ago