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WINSTONCH [101]
3 years ago
7

The mean life of a particular brand of light bulb is 1200 hours and the standard deviation is 50 hours. We can conclude that at

least 75% of this brand of bulbs will last between _______.
(A) 1100 and 1300 hours
(B) 1150 and 1250 hours
(C) 1050 and 1350 hours
(D) 1000 and 1400 hours
(E) 950 and 1450 hours
Mathematics
1 answer:
valkas [14]3 years ago
8 0

Answer:

(A) 1100 and 1300 hours

Step-by-step explanation:

In a normal distribution, we can say that 68% of the values is between the range [µ-σ;µ+σ]  with µ = the mean and σ is the standard deviation.

95% of the values are between the range [µ -2σ; µ+2σ] = [1100;1300]

99.7% of the values are between the range [µ -3σ; µ+3σ] = [1050;1350]

To find 75% of the values, we have to use the z-score

for 75% the Z-score = 1.15

This gives the range: [µ -Zσ; µ+Zσ]  ⇒ [1200 - 1.15*50;1200+1.15*50] = [1142.5 ; 1257.5]

We can say that at least 75% (or more) is in the range [1100;1300]

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vekshin1

Answer:

                                     

Step-by-step explanation:

8 0
2 years ago
A car is traveling at a steady speed. It travels 1 3/4 miles in 2 1/3 minutes. How far will it travel in 45 minutes? In 1 hour?
mina [271]

Answer:

33.75 miles in 45 minutes,

45 miles in an hour

Step-by-step explanation:

45 minutes: 2 1/3= 7/3 ---> 7/3*3=7,

                    1 3/4= 7/4 ---> 7/4*3=5.25

car travels 5.25 miles for every 7 minutes,

45/7*5.25= 33.75 miles

1 hour (60 minutes):

using that the car travels 5.25 miles for every 7 minutes,

60/7*5.25= 45 miles

Hope that makes sense!

3 0
3 years ago
In physics, if a moving object has a starting position at so, an initial velocity of vo, and a constant acceleration a, the
emmasim [6.3K]

Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

5 0
3 years ago
Y'all I am struggling Use the following functions to find each value below. f(x)=5x; g(x)=−2x+1; h(x)=x2+6x+8
Anni [7]

Answer:

see below the first three problems

Step-by-step explanation:

f(g(-2))

First, find g(-2) using function g(x). Then use that value as input for function f(x).

g(x) = -2x + 1

g(-2) = -2(-2) + 1

g(-2) = 5

f(x) = 5x

f(5) = 5(5)

f(5) = 25

f(g(-2)) = 25

g(h(3))

First, find h(3) using function h(x). Then use that value as input for function g(x).

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h(3) = 3^2 + 6(3) + 8 = 9 + 18 + 8

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f(g(3a))

First, find g(3a) using function g(x). Then use that value as input for function f(x).

g(x) = -2x + 1

g(3a) = -2(3a) + 1

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f(x) = 5x

f(-6a + 1) = 5(-6a + 1)

f(-6a + 1) = -30a + 5

f(g(3a)) = -30a + 5

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Juliette [100K]

Answer:

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Step-by-step explanation:

Using the Additive Inverse, it is the same as saying 57+17 = 74

please give brainliest, have a nice day

5 0
3 years ago
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