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3 years ago

Need help pls ! 20points no links

Mathematics

1 answer:

Elenna [48]3 years ago

7 0

Answer:

Step-by-step explanation:

We need only identify the x- and y-coordinates of the point of intersection of these two graphs. That point is (-4, 2).

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Question 3 of 10

Leya [2.2K]

The third quartile of this data set is B. 24.

6 0

3 years ago

Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

$x=3$

also solving

$x=\frac{-\left(-5\right)-\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

$x=-\frac{1}{2}$

Therefore,

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

7 0

3 years ago

Car A's fuel efficiency is 34 miles per gallon of gasoline, and car B's fuel efficiency is 23 miles per gallon of gasoline. At t

Verdich [7]

Answer:

22 more gallons.

Step-by-step explanation:

Given:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Question asked:

At those rates, how many more gallons of gasoline would car B consume than car A on a 1,564 miles trip?

Solution:

Car A's fuel efficiency is 34 miles per gallon of gasoline.

By unitary method:

Car A can travel 34 miles in = 1 gallon

Car A can travel 1 mile in = $\frac{1}{34} \ gallon$

Car A can travel 1564 miles in = $\frac{1}{34} \times1564=46\ gallons$

Car B's fuel efficiency is 23 miles per gallon of gasoline.

Car B can travel 23 miles in = 1 gallon

Car B can travel 1 mile in = $\frac{1}{23} \ gallon$

Car B can travel 1564 mile in = $\frac{1}{23} \times1564=68\ gallons$

We found that for 1564 miles trip Car A consumes 46 gallons of gasoline while Car B consumes 68 gallons of gasoline that means Car B consumes 68 - 46 = 22 gallons more gasoline than Car A.

Thus, Car B consumes 22 more gallons of gasoline than Car A consumes.

6 0

3 years ago

Libby earns $10 each hour for babysitting. Let m = the money she earns, and t = the time in hours she is babysitting. What equat

elena55 [62]

Answer:

$10t=m

Step-by-step explanation:

If for each hour is $10.

She would earn the number of hours times $10.

Example: She did babysitting for 4 hours this weekend. The equation is $10(4)=m or $10 x 4 = m. m=40

8 0

2 years ago

How many bowls of cereal did he eat pls and thx

miv72 [106K]

36 bowls - since with one gallon he can eat 12 bowls (as demonstrated by 1/12), you multiply 12 by 3 to get 36 bowls.

8 0

3 years ago

Read 2 more answers